加速UrlFetch Google App腳本？

Question

目標是貫穿約10,000條鏈接。確定哪些頁面編號> 3並突出顯示第一列。我已經完成了所有這些工作，但問題是它需要Url Fetch時間過長，我遇到了最大運行時錯誤。無論如何，我可以加快這個代碼，所以我可以通過10,000行？

function readColumns() { 
    //program is going to run through column 3 by going through the amount of rows, truncating last three characters to see if pdf, then highlighting first column 
    var sheet = SpreadsheetApp.getActiveSheet(); 
    var columns = sheet.getDataRange(); 
    var rowNum = columns.getNumRows(); 
    var values = columns.getValues(); 
    var html; 
    var htmlString; 

    for(var i = 1; i <= rowNum; i++){ 
    var columnLogger = values[i][2]; 
    try{ 
     html = UrlFetchApp.fetch(values[i][2], 
     { 
     muteHttpExceptions: true, 
     } 
    ); 
    }catch(e){ 
     Logger.log("Error at line " + i); 
     var error = true; 
    } 
    htmlString = html.getContentText(); 
    var index = htmlString.indexOf("Pages") + 6; 
    var pageNumber = parseInt(htmlString.charAt(index),10); 

    var lastChars = "" + columnLogger.charAt(columnLogger.length-3) + columnLogger.charAt(columnLogger.length-2) + columnLogger.charAt(columnLogger.length-1); 

    if((error) || (!lastChars.equals("pdf") && values[i][6].equals("") && !pageNumber >= 3)){ 

     //goes back to first column and highlights yellow 
     var cellRange = sheet.getRange(1, 1, rowNum, 3) 
     var cell = cellRange.getCell(i+1, 1) 
     cell.setBackground("yellow"); 
    } 


    } 


} 

編輯 - 短腳本：有了這個

var lastChars = "" + columnLogger.charAt(columnLogger.length-3) + columnLogger.charAt(columnLogger.length-2) + columnLogger.charAt(columnLogger.length-1); 

：

function foreverCall(){ 
    var start = 1480; 

    for(;;){ 
    readColumns(start); 
    start = start + 100; 
    } 

} 


function readColumns(start) { 
    //program is going to run through column 3 by going through the amount of rows, truncating last three characters to see if pdf, then highlighting first column 
    var sheet = SpreadsheetApp.getActiveSheet(); 
    var columns = sheet.getDataRange(); 
    var rowNum = columns.getNumRows(); 
    var values = columns.getValues(); 
    var html; 
    var htmlString; 
    var error; 

    for(var i = start; i < start+100; i++){ 
    if(loop(values, error, html, htmlString, rowNum, sheet, columns, i)){ 

     var cellRange = sheet.getRange(1, 1, rowNum, 3) 
     var cell = cellRange.getCell(i, 1) 
     cell.setBackground("yellow"); 

    } 
    } 


} 

function loop(values, error, html, htmlString, rowNum, sheet, columns, i){ 
    var columnLogger = values[i][2]; 


    var lastChars = columnLogger.slice(-4); 

    if(!lastChars.equals(".pdf") && values[i][6].equals("")){ 


     return true; 


    }else{ 

     try{ 
     error = false 
     html = UrlFetchApp.fetch(values[i][2].toString()); 
     if(html == null){ 
      error = true; 
     } 
     }catch(e){ 
     Logger.log("Error at line " + i); 
     error = true; 
     } 
     if(!error){ 
     htmlString = html.getContentText(); 
     var index = htmlString.indexOf("Pages") + 6; 
     var pageNumber = parseInt(htmlString.charAt(index),10); 

     } 
     //goes back to first column and highlights yellow 
     if(error || !pageNumber >= 3){ 
     return true; 
     } 
    } 

    return false; 

} 

Answer 1

您可以更換該

var lastChars = columnLogger.slice(-3); 

您也可以從html側邊欄或對話框啓動抓取腳本來運行短批次，然後返回到成功處理程序，然後根據返回值啓動另一批次。返回值也可以用來在下一行開始下一批。它實際上需要更長的時間才能運行，但通過保持批量很小，您可以保持在腳本限制之下。

Answer 2

可以與線替換

變種lastChars = columnLogger.slice（-3）;