我有一個示例文件,它從文件中讀取內容。內容的格式不可讀,如下所示。當我使用read()函數和變量cout時,它將返回相同的二進制數據,而不是顯示普通文本。如何以人性可讀的格式讀取內容?C++ read()返回無格式的二進制數據
以下是文件的內容(根據使用write()函數)我讀:
LÀ ³ L¹ R
這裏是閱讀代碼:
void readBinary(){
ifstream inputFile("flights.dat", ios::in | ios::binary);
char buffer[100];
inputFile.seekg(0, ios::beg);
if(inputFile.is_open()){
inputFile.read((char *)&buffer, sizeof(buffer));
for(int i = 0; i < sizeof(buffer); i++){
cout << buffer[i];
}
}
inputFile.close();
}
這裏是代碼寫入數據:
#include <iostream>
#include <fstream>
#include <string>
#include <cstdlib>
using namespace std;
void inputData();
struct airplaneDetails {
string airplaneCode;
int totalRows, seatsInRows, firstSeats, businessSeats, economySeats;
};
int main(){
inputData();
return 0;
}
void inputData(){
ofstream outputFile("flights.dat", ios::out | ios::binary | ios::app);
if(!outputFile.is_open()){
cout << "There was an error opening the file.";
} else {
airplaneDetails airplane;
cout << "Please provide the details below :" << "\n\n";
cout << "Enter the airplane code : ";
cin >> airplane.airplaneCode;
.
.
//Assigning values to the variables
.
.
//Put the pointer at the end
outputFile.seekp(0, ios::end);
//Write the input data to the binary file
outputFile.write((char *)&airplane.airplaneCode, sizeof(airplane.airplaneCode));
outputFile.write((char *)&airplane.totalRows, sizeof(airplane.totalRows));
outputFile.write((char *)&airplane.seatsInRows, sizeof(airplane.seatsInRows));
outputFile.write((char *)&airplane.firstSeats, sizeof(airplane.firstSeats));
outputFile.write((char *)&airplane.businessSeats, sizeof(airplane.businessSeats));
outputFile.write((char *)&airplane.economySeats, sizeof(airplane.economySeats));
//Close the file handler
outputFile.close();
}
}
對不起,但我不確定你期望在這裏看到什麼,你能再解釋一下嗎? – vu1p3n0x
令我驚訝的是,當您讀取一個文件並打印剛纔讀取的數據時,它會打印文件的內容。 – immibis
使用'inputFile.gcount()'來確定從文件中讀取了多少字節。 – dreamlax