我想簡單地寫一個查詢,它只爲每個結果行取代一列(從...中選擇標題),而不是全部(select * ... from)。我的SQL查詢將是:油滑:選擇不工作的列
select titel from Lied;
根據http://slick.typesafe.com/doc/3.1.1/sql-to-slick.html?highlight=case#id3我應該能夠通過簡單地做這樣的事情在光滑3.1只選擇幾個列:
people.map(p => (p.age, p.name ++ " (" ++ p.id.asColumnOf[String] ++ ")")).result
對我來說,這將意味着:
lieds.map(x => (x.titel)).result.map { println }
這不起作用。 Eclipse說:
No matching Shape found. Slick does not know how to map the given types. Possible causes: T in Table[T] does not match your * projection. Or you use an unsupported type in a Query (e.g. scala List). Required level: slick.lifted.FlatShapeLevel Source type: slick.lifted.Rep[String] Unpacked type: T Packed type: G
我應該如何解決這個問題?我想我還是不能在這裏結合一些基礎知識,儘管讀scala slick method I can not understand so far(不知道這是否仍然適用於光滑3.1)和光滑的3.1文檔。
我的表(從光滑的生成):
case class LiedRow(id: Long, titel: String, rubrikId: Option[Long] = None, stichwoerter: Option[String] = None, bemerkungen: Option[String] = None, createdAt: Option[java.sql.Timestamp] = None, updatedAt: Option[java.sql.Timestamp] = None, externallink: Option[String] = None, lastedituserId: Long, tonality: Option[String] = None)
implicit def GetResultLiedRow(implicit e0: GR[Long], e1: GR[String], e2: GR[Option[Long]], e3: GR[Option[String]], e4: GR[Option[java.sql.Timestamp]]): GR[LiedRow] = GR{
prs => import prs._
LiedRow.tupled((<<[Long], <<[String], <<?[Long], <<?[String], <<?[String], <<?[java.sql.Timestamp], <<?[java.sql.Timestamp], <<?[String], <<[Long], <<?[String]))
}
class Lied(_tableTag: Tag) extends Table[LiedRow](_tableTag, "lied") {
def * = (id, titel, rubrikId, stichwoerter, bemerkungen, createdAt, updatedAt, externallink, lastedituserId, tonality) <> (LiedRow.tupled, LiedRow.unapply)
def ? = (Rep.Some(id), Rep.Some(titel), rubrikId, stichwoerter, bemerkungen, createdAt, updatedAt, externallink, Rep.Some(lastedituserId), tonality).shaped.<>({r=>import r._; _1.map(_=> LiedRow.tupled((_1.get, _2.get, _3, _4, _5, _6, _7, _8, _9.get, _10)))}, (_:Any) => throw new Exception("Inserting into ? projection not supported."))
val id: Rep[Long] = column[Long]("id", O.AutoInc, O.PrimaryKey)
val titel: Rep[String] = column[String]("Titel")
val rubrikId: Rep[Option[Long]] = column[Option[Long]]("rubrik_id", O.Default(None))
val stichwoerter: Rep[Option[String]] = column[Option[String]]("Stichwoerter", O.Default(None))
val bemerkungen: Rep[Option[String]] = column[Option[String]]("Bemerkungen", O.Default(None))
val createdAt: Rep[Option[java.sql.Timestamp]] = column[Option[java.sql.Timestamp]]("created_at", O.Default(None))
val updatedAt: Rep[Option[java.sql.Timestamp]] = column[Option[java.sql.Timestamp]]("updated_at", O.Default(None))
val externallink: Rep[Option[String]] = column[Option[String]]("externalLink", O.Default(None))
val lastedituserId: Rep[Long] = column[Long]("lastEditUser_id")
val tonality: Rep[Option[String]] = column[Option[String]]("tonality", O.Length(30,varying=true), O.Default(None))
lazy val rubrikFk = foreignKey("liedRubrik", rubrikId, Rubrik)(r => Rep.Some(r.id), onUpdate=ForeignKeyAction.Cascade, onDelete=ForeignKeyAction.NoAction)
lazy val userFk = foreignKey("liedLastEditUser", lastedituserId, User)(r => r.id, onUpdate=ForeignKeyAction.Cascade, onDelete=ForeignKeyAction.NoAction)
}
lazy val Lied = new TableQuery(tag => new Lied(tag))
我不完全理解你的問題,但也許這個教程可以幫助你:http://pedrorijo.com/blog/play-slick/ – pedrorijo91
感謝您的鏈接。我已經看到了。不幸的是我找不到可以回答我的問題的東西。 如何清除我的問題?在一句話中,我想要一個只選擇一列(標題)而不是全部(*)的光滑語句,因爲我不需要該特定查詢中其他列的值。 – Philipp
它應該像 那樣簡單'def getTitelById(id:Long)= lieds.filter(_。id === id).map(_。titel)' 然後您可以使用'db.run(getTitelById 1032L)'得到未來[String] – Qingwei