如何忽略查詢結果中的第一個零位

Question

我想忽略生產的第一天是否有零值。

SELECT D_DATE, PRODUCE FROM PRODUCTION 

數據集

Date   Produce 
1/1/2015  0 
1/2/2015  0 
1/3/2015  0 
1/4/2015  6 
1/5/2015  5 
1/6/2015  2 
1/7/2015  0 
1/8/2015  1 
1/9/2015  1 

前三天是零，我想在我的結果忽略，但第7天不應該被忽視

所需的結果

Date   Produce 
1/4/2015  6 
1/5/2015  5 
1/6/2015  2 
1/7/2015  0 
1/8/2015  1 
1/9/2015  1 

Answer 1

爲簡單起見我假定有至少一天以產生> 0

SELECT d_date, produce 
FROM production 
WHERE 
    d_date >= (
     SELECT MIN(d_date) 
     FROM production 
     WHERE 
      produce != 0 
    ) 
; 

Answer 2

假設你的日期是在DATETIME，這會幫助你嗎？

SELECT D_DATE, PRODUCE 
FROM PRODUCTION 
where Date >= (select TOP 1 Date from PRODUCTION where PRODUCE > 0 Order by DATE) 

Answer 3

試試這個

SELECT date, 
     produce 
FROM 
(
SELECT date, 
     produce, 
     row_number() over (order by date) r1, 
     row_number() over (order by produce, date) r2 
FROM production 
) A 
WHERE r1 != r2 

Answer 4

使用相關子查詢。

SELECT Date, Produce, 
ROW_NUMBER() OVER (ORDER BY DATE) RN 
INTO #Temp 
FROM tbl 

SELECT t.Date, t.Produce FROM #Temp t 
WHERE 
EXISTS(
       SELECT 1 FROM #Temp t1 
        WHERE t1.rn < t.rn 
        AND t1.PRODUCE !=0) 
OR T.Produce != 0 

Fiddle here

Answer 5

可以使用SUM作爲分析函數來計算產生的累積和和過濾那些大於零。

select d_date, produce 
from (
     select 
     d_date, 
     produce, 
     sum(produce) over (order by d_date) cuml_produce 
     from production 
) 
where cuml_produce > 0 
order by d_date;