無法讀取使用LINQ to XML的XML註釋

Question

我無法檢索XML節點註釋。有沒有不同的方式來檢索它？ 。價值也沒有工作。我在StackOverflow中找不到任何東西。 這是我在做什麼：

<?xml version="1.0" encoding="utf-8"?> 
<components> 
    <component name="AAA"> 
     <sample> 
      <!-- blah blah blah --> 
     </sample> 
     <data> 
      <!-- blah blah blah -->    
     </data> 
    </component> 

    <component name="BBB"> 
     <sample> 
      <!-- blah blah blah --> 
     </sample> 
     <data> 
      <!-- blah blah blah -->    
     </data>  
    </component>  
</components> 

public class Component 
{ 
    public string Name { get; set; } 
    public string Sample { get; set; } 
    public string Data { get; set; } 
} 

    XDocument doc = XDocument.Load(xmlFileName); 

    Component components = doc.Descendants("component") 
     .Select(x => new Component 
     { 
      Name = (string)x.Attribute("name"), 
      Sample = (string)x.Element("sample"), //cannot read value 
      Data = (string)x.Element("data") //cannot read value 
     }); 

任何想法？

Answer 1

我發現在這個環節的解決方案：https://msdn.microsoft.com/en-us/library/bb675167.aspx 因此，代碼最終看上去像這樣：

var components = doc 
     .Descendants("component") 
     .Select(x => new Component() 
     { 
      Name = (string)x.Attribute("name"), 
      Sample = x.Element("sample").Nodes().OfType<XComment>() 
                   .Select(s=>s.Value) 
                   .Aggregate(
                    new StringBuilder(), 
                    (s,i)=>s.Append(i), 
                    s => s.ToString() 
                   ), 
      Data = x.Element("data").Nodes().OfType<XComment>() 
                   .Select(s=>s.Value) 
                   .Aggregate(
                    new StringBuilder(), 
                    (s,i)=>s.Append(i), 
                    s => s.ToString() 
                   ) 
     }); 

Answer 2

試試這個：

var components = 
    doc 
     .Descendants("component") 
     .Select(x => new Component() 
     { 
      Name = (string)x.Attribute("name"), 
      Sample = String.Join("", x.Element("sample").Nodes().OfType<XComment>()), 
      Data = String.Join("", x.Element("data").Nodes().OfType<XComment>()), 
     });