首先,我是新的JAVA AWS Eclipse Maven Tomcat ...嘗試下面的代碼時遇到以下錯誤..錯誤是「HTTP狀態500 -java。 lang.NoClassDefFoundError:無法初始化類com.amazonaws.services.sqs.AmazonSQSClient」 ......無法初始化類com.amazonaws.services.sqs.AmazonSQSClient
package sms.pii.webservice;
import com.amazonaws.auth.BasicAWSCredentials;
import com.amazonaws.services.sqs.AmazonSQS;
import com.amazonaws.services.sqs.AmazonSQSClient;
import com.amazonaws.services.sqs.model.*;
public class AWSSimpleQueueServiceUtil {
public BasicAWSCredentials credentials;
public AmazonSQS sqs;
public AWSSimpleQueueServiceUtil(){
try{
String accessKey= "xxxxxx";
String secretKey= "xxxxxxxx";
this.credentials = new BasicAWSCredentials(accessKey,secretKey);
this.sqs = new AmazonSQSClient(this.credentials);
//this.sqs.setEndpoint("https://sqs.ap-southeast-1.amazonaws.com");
}
catch(Exception e){
System.out.println("exception while creating awss3client : " + e);
}
}
public String createNewQueue(String queueName){
CreateQueueRequest createQueueRequest = new CreateQueueRequest(queueName);
String queueUrl = this.sqs.createQueue(createQueueRequest).getQueueUrl();
return queueUrl;
}
public String getQueueUrlByName(String queueName){
GetQueueUrlRequest getQueueUrlRequest = new GetQueueUrlRequest(queueName);
return this.sqs.getQueueUrl(getQueueUrlRequest).getQueueUrl();
}
public ListQueuesResult listAllQueues(){
return this.sqs.listQueues();
}
}
package sms.pii.webservice;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import sms.pii.webservice.AWSSimpleQueueServiceUtil;
@Path("/Queue")
public class TestSQS {
@GET
@Path("/Name/{name}")
@Produces(MediaType.APPLICATION_JSON)
public Student produceJSON(@PathParam("name") String name) {
Student st = new Student(name, "kumar",55,21);
return st;
}
@GET
@Path("/createQueue/{name}")
@Produces(MediaType.TEXT_PLAIN)
public String createQueue(@PathParam("name") String queueName){
AWSSimpleQueueServiceUtil test = new AWSSimpleQueueServiceUtil();
return test.createNewQueue(queueName);
}
@GET
@Path("/getQueueUrl/{name}")
@Produces(MediaType.TEXT_PLAIN)
public String getQueueUrl(@PathParam("name") String queueName){
AWSSimpleQueueServiceUtil test = new AWSSimpleQueueServiceUtil();
return test.getQueueUrlByName(queueName);
}
}
的pom.xml
<dependencies>
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-server</artifactId>
<version>1.9</version>
</dependency>
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-json</artifactId>
<version>1.9</version>
</dependency>
<dependency>
<groupId>com.amazonaws</groupId>
<artifactId>aws-java-sdk</artifactId>
<version>1.8.9.1</version>
</dependency>
<dependency>
<groupId>commons-logging</groupId>
<artifactId>commons-logging</artifactId>
<version>1.1.1</version>
</dependency>
我錯過了「Maven Dependency」(B-配置階段)....享受100Bounty花花公子.. – Naveenkumar 2014-09-08 09:57:10
它因爲你的eclipse項目並沒有被創建爲「Maven項目」。你可以在Eclipse中創建一個新的項目:文件 - >新建 - >其他。然後在嚮導「Maven Project」中選擇。然後將您的maven配置爲Webapp原型。可以嗎? – arthur 2014-09-08 10:01:02
是啊,我已經創建爲web項目,然後我轉換爲maven項目..在那裏我做了一個錯誤..我15天寶寶到java .. :-)將在未來正確.. – Naveenkumar 2014-09-08 10:14:19