我在寫一個將Lua嵌入到C程序中的簡單測試。隱式聲明luaL_openlibs
我在Windows/Mingw和Linux上遇到同樣的問題。 這裏是gcc的命令我在Linux上使用:
gcc -Wall -o test_lua lua_test.c -I/usr/include/lua5.1 -llua5.1
在Windows上:
gcc -Wall -o test_lua.exe lua_test.c -llua5.1
在這兩種情況下,我有以下警告:
warning: implicit declaration of function
'luaL_openlibs' [-Wimplicit-function-declaration]
程序作品,但也許我不要使用任何標準的Lua庫? 爲什麼我會收到此警告?我在lauxlib.h
中看到luaL_openLibs
的定義!
這裏是C部分:
#include <lua.h>
#include <lauxlib.h>
#include <stdlib.h>
#include <stdio.h>
int main(int argc, char *argv[]) {
int status;
lua_State *L;
L = luaL_newstate();
// Init lua
luaL_openlibs(L);
// Load script
status = luaL_loadfile(L,"lua_test.lua");
if (status) {
fprintf(stderr,"Couldn't load file\n");
exit(1);
}
// Push data
lua_pushnumber(L, 5000);
lua_setglobal(L, "clife");
lua_pushnumber(L, 6000);
lua_setglobal(L, "ttime");
lua_pushnumber(L, 3000);
lua_setglobal(L, "atime");
// Run script
int result = lua_pcall(L, 0, LUA_MULTRET, 0);
if (result) {
fprintf(stderr,"Failed to run script: %s\n", lua_tostring(L,-1));
exit(1);
}
// Value at top of the stack is the result
const char *schedule = lua_tostring(L,-1);
fprintf(stdout,"Computed schedule is: %s\n", schedule);
// Close lua
lua_pop(L, 1);
lua_close(L);
return 0;
}
這裏是Lua的部分:
io.write("lua_test.lua -- will generate schedule\n")
io.write("Wizard life is " .. clife .. "\n")
schedule = ""
ctime = ttime - atime
if clife > 4500 then
schedule = schedule .. "[" .. ctime .. ",p]"
schedule = schedule .. "[" .. ctime+500 .. ",a]"
schedule = schedule .. "[" .. ctime+1000 .. ",i]"
schedule = schedule .. "[" .. ctime+1500 .. ",n]\n"
else
schedule = schedule .. "[" .. ctime .. ",d]"
schedule = schedule .. "[" .. ctime+500 .. ",r]"
schedule = schedule .. "[" .. ctime+1000 .. ",a]"
schedule = schedule .. "[" .. ctime+1500 .. ",i]"
schedule = schedule .. "[" .. ctime+1500 .. ",n]\n"
end
io.write("Returning " .. schedule .. "\n");
return schedule
看來是它的最後安息之地;它是5.3,這仍然是事實。 – Qix