我想這是一個簡單的函數&我錯過了編碼的地方。尋求幫助。顯示一個php的計算值並將其傳遞到數據庫
我得到用戶的輸入日期&添加/計算工作日。當我從數據庫檢索輸入時,顯示的代碼&顯示。但我想計算用戶通過提交按鈕將輸入&傳遞給數據庫的日子。
這是我的編碼。請幫助
<?php
include_once('confiq.php');
// Only process the form if $_POST isn't empty
if (! empty($_POST)) {
// Connect to MySQL
$mysqli = new mysqli('localhost', 'root', '', 'fiber');
// Check our connection
if ($mysqli->connect_error) {
die('Connect Error: ' . $mysqli->connect_errno . ': ' . $mysqli->connect_error);
}
// Insert our data
$sql = "INSERT INTO fiberexcel (SiteID0, SiteName1, SiteAddress2, ProjectType3, ReqDate4, TargetDate5, Vendor6, ESRNo7, Contact8, Engineer9, AM10)
VALUES ('{$mysqli->real_escape_string($_POST['SiteID0'])}',
'{$mysqli->real_escape_string($_POST['SiteName1'])}' ,
'{$mysqli->real_escape_string($_POST['SiteAddress2'])}',
'{$mysqli->real_escape_string($_POST['ProjectType3'])}',
'{$mysqli->real_escape_string($_POST['ReqDate4'])}',
'{$mysqli->real_escape_string($_POST['TargetDate5'])}',
'{$mysqli->real_escape_string($_POST['Vendor6'])}',
'{$mysqli->real_escape_string($_POST['ESRNo7'])}',
'{$mysqli->real_escape_string($_POST['Contact8'])}',
'{$mysqli->real_escape_string($_POST['Engineer9'])}',
'{$mysqli->real_escape_string($_POST['AM10'])}')";
$insert = $mysqli->query($sql);
// Print response from MySQL
if ($insert) {
echo "!";
} else {
die("Error: {$mysqli->errno} : {$mysqli->error}");
}
// Close our connection
$mysqli->close();
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Create Customer</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<link href="css/layout1.css" media="screen" rel="stylesheet" type="text/css">
<link rel="stylesheet" type="text/css" href="css/font-awesome.css">
</head>
<body>
<div id="wrapper">
<div id="home"><a href="index.html"><img src="./img/home.png"></img></a>
</div>
<h2><u>CREATE CUSTOMER</u></h2>
<form action="Create.php" method="post">
<table border="0" align="left" cellspacing="30" height="5">
<tr><td><b>Site ID:</b></td> <td><input type="text" id="SiteID0" name="SiteID0" size="35" required="required"><br></td></tr>
<tr><td><b>Site Name:</b></td> <td><input type="text" id="SiteName1" name="SiteName1" size="35" required="required"><br></td></tr>
<tr><td><b>Site Address:</b></td> <td><input type="text" id="SiteAddress2" name="SiteAddress2" size="35" required="required"><br></td></tr>
<tr><td><b>Project Type:</b></td> <td><input type="text" id="ProjectType3" name="ProjectType3" size="35"><br></td></tr>
<tr><td><b>Requested Date:</b></td> <td><input type="date" id="ReqDate4" name="ReqDate4" size="35"><br></td></tr>
<tr><td><b>Target Completion Date</b></td>
<td><input type="date" id="TargetDate5"
<?php
$ReqDate4= date("Y-m-d"); //increment 75 days
$TargetDate5 = strtotime($ReqDate4."+ 75 weekday");
echo date("Y-m-d",$TargetDate5) . "\n";
echo "</td>";
$_POST['$TargetDate5 ']=$TargetDate5 ;
echo "</td>";
;?>
<br></td></tr>
<tr><td><b>Vendor:</b></td> <td><input type="text" id="Vendor6" name="Vendor6" size="35" required="required"><br></td></tr>
<tr><td><b>ESR No:</b></td> <td><input type="text" id="ESRNo7" name="ESRNo7" size="35" ><br></td></tr>
<tr><td><b>Contact Details:</b></td> <td><input type="text" id="Contact8" name="Contact8" size="35" ><br></td></tr>
<tr><td><b>Engineer:</b></td> <td><input type="text" id="Engineer9" name="Engineer9" size="35" required="required"><br></td></tr>
<tr><td><b>Account Manager:</b></td> <td><input type="text" id="AM10" name="AM10" size="35" ><br></td></tr>
<tr>
<td></td><td><input type="submit" value="Submit" name="action" /></td>
<td><input type ="submit" value="Clear" onclick="reset();"></td>
</tr>
</form>
</table>
</div>
</body>
</html>
謝謝。但這不是我的要求。 「請求日期」字段將由用戶給出。我想爲該輸入添加日期,將其顯示在「TagetDate」字段中,並將計算的日期值傳遞給數據庫。我有一個不同的頁面來顯示錶格中的用戶輸入。那裏的計算只在頁面中有效,而不是存儲在數據庫中。請幫助 – Sugs