0
viewclass= input("choose a class number and either alphabetically, average or highest?")#type in what you want to select
if viewclass=='1 average':#variable inputted
with open("1.txt") as f:#open text file
d = {}
for line in f:
column = line.split(":")#split name and score
names = column[0]#names in column
scores = int(column[1].strip())
count = 0
while count < 3:
d.setdefault(names, []).append(scores)#name and scores added to end of list
count = count + 1
for names, v in sorted(d.items()):#sorted
average = (sum(v)/len(v))
print(names,average)#average score printed
averages=[]
averages.append(average)
elif viewclass=='2 average':
with open("2.txt") as f:
d = {}
for line in f:
column = line.split(":")
names = column[0]
scores = int(column[1].strip())
count = 0
while count < 3:
d.setdefault(names, []).append(scores)
count = count + 1
for names, v in sorted(d.items()):
average = (sum(v)/len(v))
print(names,average)
averages=[]
averages.append(average)
elif viewclass=='3 average':
with open("3.txt") as f:
d = {}
for line in f:
column = line.split(":")
names = column[0]
scores = int(column[1].strip())
count = 0
while count < 3:
d.setdefault(names, []).append(scores)
count = count + 1
for names, v in sorted(d.items()):
average = (sum(v)/len(v))
print(names,average)
averages=[]
averages.append(average)
我的其他代碼的作品,但在這個時候我運行信號文件時,它的工作原理,但是當我選擇它,我得到這個錯誤排序錯誤
choose a class number and either alphabetically, average or highest?1 average
Traceback (most recent call last):
File "C:/Users//Documents/New folder (2)/14343 - Copy.py", line 10, in <module>
for line in f:
ValueError: I/O operation on closed file.