我正在使用play framework和Scala。如何使用播放框架在scala中將列表數據轉換爲Json?
我有以下列表 -
List(
(C: - read,1412750402124,46552070),
(C: - write,1412750402124,433057),
(E: - read,1412750402124,5435),
(E: - write,1412750402124,1728),
(F: - read,1412750402124,5435),
(F: - write,1412750402124,1728),
(C: - read,1412750402125,46552071),
(C: - write,1412750402125,433060),
(E: - read,1412750402125,5445),
(E: - write,1412750402125,1730),
(F: - read,1412750402125,5450),
(F: - write,1412750402125,1428)
)
我想下面的輸出 -
key:[
{"name":"C:-read",
data:[[1412750402124,46552070],[1412750402125,46552071]...]
},
{
"name":"C:-write",
data:[[1412750402124,433057],[1412750402125,433060]...]
},
{
"name":"E:-read",
data:[[1412750402124,5435],[1412750402125,5445]...]
},
{
"name":"E:-write",
data:[[1412750402124,1728],[1412750402124,1730]...]
},
{
"name":"F:-read",
data:[[1412750402124,5435],[1412750402125,5450]...]
},
{
"name":"F:-write",
data:[[1412750402124,1728],[1412750402124,1428]...]
}
]
使用Scala中如何獲得上述輸出?