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我想從服務器獲取json並將其反序列化,但我嘗試使用未轉義的控制字符。 我的代碼如下...swift非轉義控制字符
let urlFinal = "http://000.0000.000.000:8080"
let jsonUrl = urlFinal
let session = NSURLSession.sharedSession()
let shotsUrl = NSURL(string: jsonUrl)
let task = session.dataTaskWithURL(shotsUrl!) {data, response, error in
guard data != nil else {
falha()
return
}
//let json = JSON(data: data!)
//print(json["ServicoCliente"][0]["id"])
do {
let jsonData = try NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.MutableContainers)
let J = jsonData as! NSDictionary
print(jsonData)
let us = J["ServicoCliente"]
print(us)
dispatch_async(dispatch_get_main_queue(),{
sucesso()
});
} catch _ {
falha()
}
}
task.resume()
,我也試過這種使用Alamofire 3.0:
Alamofire.request(.GET, "http://000.000.000.000/", parameters: nil)
.responseJSON { response in
debugPrint(response) // prints detailed description of all response properties
print(response.request) // original URL request
print(response.response) // URL response
print(response.data) // server data
print(response.result) // result of response serialization
if let JSON = response.result.value {
print("JSON: \(JSON)")
}
}
而得到這個錯誤:
Unescaped control character around character 263
如何刪除字符不逃逸?
我用X-代碼7.3.1和SWIFT 2.3
UPDATE: 的Json
{"ServicoCliente":[{"id":"195","cliente":"247","enderecoFavoritos":"48","servicoProfissional":"194","ind_estado_cliente":"A","ind_estado_profissional":"","profissional_id":"240","profissional_nome":"PetMax","servicotipo_nome":"Petshop","servicosubtipo_nome":"Tosa ","dta_inc_alt":"2016-11-05 22:56:19.333","ind_finalizado":"N"}]}
我認爲你的JSON無效,請嘗試將此objc代碼轉換爲Swift http://stackoverflow.com/a/11192483/6366256 –
請將您的JSON字符串粘貼到此處,這有助於我們調查您的問題。 – Enix
我用json更新了,但是在我的一個測試中,我複製並粘貼了textField中的json,然後工作。我認爲該字符在複製或automaticamet中丟失轉換爲文本字段@Enix –