提到的變通辦法爲HHH-9114 bug邁克爾工作,例如,在我的情況下,通過向TwitterListedCount
:(注意,這兩個@Id
和@Type
必須添加的仍然正常用戶類型)與模式生成使用時
// TODO: https://hibernate.atlassian.net/browse/HHH-9114
@Override @Id
public long getTwitterUserId() {
return super.getTwitterUserId();
}
@Override @Id
public DateTime getFetchTime() {
return super.getFetchTime();
}
BTW,解決辦法有nasty side-effect HHH-9350,它產生重複的組合柱:
CREATE TABLE buzz.twitterlistedcount
(
id_fetchtime timestamp without time zone NOT NULL,
id_twitteruserid bigint NOT NULL,
_identifiermapper_fetchtime timestamp without time zone NOT NULL,
_identifiermapper_twitteruserid bigint NOT NULL,
listedcount integer NOT NULL,
CONSTRAINT twitterlistedcount_pkey PRIMARY KEY (id_fetchtime, id_twitteruserid)
)
WITH (
OIDS=FALSE
);
我試着不使用@MappedSuperclass
可言,但錯誤模式生成仍然發生。順便說一句,我正在使用DefaultComponentSafeNamingStrategy
這可能是錯誤所在。這可能是一個不同的錯誤,在Hibernate find with composite key. Invalid column name Exception
問正確的解決方法涉及手動添加@Column(name=)
,這與模式生成效果很好:
@Id
@Basic()
@Column(name="twitteruserid")
private long twitterUserId = 0;
@Id
@Basic()
@Column(name="fetchtime")
@Type(type = "org.jadira.usertype.dateandtime.joda.PersistentDateTime")
private DateTime fetchTime = null;
僅供參考,與Spring Data JPA一起使用時,它需要從MappedSuperclass
中刪除@Id
和@Type
註釋。如果這些不被刪除,將會有錯誤。它不會改變這個Hibernate bug的性質,BTW。
org.springframework.data.mapping.model.MappingException: Ambiguous mapping! Annotation Id configured on field twitterUserId and one of its accessor methods in class TwitterFollowerCount!
at org.springframework.data.mapping.model.AnnotationBasedPersistentProperty.populateAnnotationCache(AnnotationBasedPersistentProperty.java:111)
at org.springframework.data.mapping.model.AnnotationBasedPersistentProperty.<init>(AnnotationBasedPersistentProperty.java:66)
at org.springframework.data.jpa.mapping.JpaPersistentPropertyImpl.<init>(JpaPersistentPropertyImpl.java:86)
at org.springframework.data.jpa.mapping.JpaMetamodelMappingContext.createPersistentProperty(JpaMetamodelMappingContext.java:67)
at org.springframework.data.jpa.mapping.JpaMetamodelMappingContext.createPersistentProperty(JpaMetamodelMappingContext.java:35)
at org.springframework.data.mapping.context.AbstractMappingContext$PersistentPropertyCreator.createAndRegisterProperty(AbstractMappingContext.java:449)
at org.springframework.data.mapping.context.AbstractMappingContext$PersistentPropertyCreator.doWith(AbstractMappingContext.java:427)
at org.springframework.util.ReflectionUtils.doWithFields(ReflectionUtils.java:607)
at org.springframework.data.mapping.context.AbstractMappingContext.addPersistentEntity(AbstractMappingContext.java:295)
at org.springframework.data.mapping.context.AbstractMappingContext.addPersistentEntity(AbstractMappingContext.java:257)
at org.springframework.data.mapping.context.AbstractMappingContext.initialize(AbstractMappingContext.java:373)
at org.springframework.data.jpa.repository.config.JpaRepositoryConfigExtension$JpaMetamodelMappingContextFactoryBean.createInstance(JpaRepositoryConfigExtension.java:216)
at org.springframework.data.jpa.repository.config.JpaRepositoryConfigExtension$JpaMetamodelMappingContextFactoryBean.createInstance(JpaRepositoryConfigExtension.java:169)
at org.springframework.beans.factory.config.AbstractFactoryBean.afterPropertiesSet(AbstractFactoryBean.java:134)
at org.springframework.data.jpa.repository.config.JpaRepositoryConfigExtension$JpaMetamodelMappingContextFactoryBean.afterPropertiesSet(JpaRepositoryConfigExtension.java:230)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1612)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1549)
... 40 more
當我得到一些意見,但沒有答案,我應該假設,這個星座是不可能的。我只是無法在文檔中找到提示... – austrianuser 2010-12-02 08:31:25