爲什麼我的代碼「破」出循環？

Question

fileName = raw_input("Enter the filename: ") 
n = input("Enter the line you want to look: ") 
f = open(fileName,'r') 
numbers = [] 

for line in f: 
    sentenceInLine = line.split('\n') 
    for word in sentenceInLine: 
      if word != '': 
       numbers.append(word) 
print numbers 
print len(numbers) 
print numbers[n-1] 

if n == 0: 
    print "There is no 0 line" 
    break 

Answer 1

我想你錯過分裂sentenceInLine像sentenceInLine.split(' ')

Answer 2

你遍歷每一行，然後你根據'\n'分割線。 \ n是換行符。那會混淆你的邏輯。

Answer 3

因此，你試圖做的事情有點令人困惑，但你應該在用戶輸入n的值後檢查n。不在最後。

你可能想也搭上那裏的文件不能被發現，我認爲這是你需要什麼異常：當用戶輸入n = 0時，該程序退出

fileName = raw_input("Enter the filename: ") 
n = input("Enter the line you want to look: ") 
if n == 0: 
    print "There is no 0 line" 
    sys.exit(); 

try: 
    f = open(fileName,'r') 
except IOError: 
    print "Could not find file" 
    sys.exit()