使用javascript返回JSON解析[對象對象]

-1

我正在製作一個簡單的網頁，將地址作爲輸入並使用谷歌地址geocodeapi返回該地址的經度和緯度。我無法處理結果。我想選擇特定的元素，即從谷歌響應返回的JSON的經度和緯度。請幫助我我是JSON的新手。這裏是JSON：使用javascript返回JSON解析[對象對象]

{ 
    "results" : [ 
    { 
     "address_components" : [ 
     { 
      "long_name" : "Jabalpur", 
      "short_name" : "Jabalpur", 
      "types" : [ "locality", "political" ] 
     }, 
     { 
      "long_name" : "Jabalpur", 
      "short_name" : "Jabalpur", 
      "types" : [ "administrative_area_level_2", "political" ] 
     }, 
     { 
      "long_name" : "Madhya Pradesh", 
      "short_name" : "MP", 
      "types" : [ "administrative_area_level_1", "political" ] 
     }, 
     { 
      "long_name" : "India", 
      "short_name" : "IN", 
      "types" : [ "country", "political" ] 
     }, 
     { 
      "long_name" : "482001", 
      "short_name" : "482001", 
      "types" : [ "postal_code" ] 
     } 
     ], 
     "formatted_address" : "Jabalpur, Madhya Pradesh 482001, India", 
     "geometry" : { 
     "bounds" : { 
      "northeast" : { 
      "lat" : 23.246354, 
      "lng" : 80.08003219999999 
      }, 
      "southwest" : { 
      "lat" : 23.1050362, 
      "lng" : 79.85747339999999 
      } 
     }, 
     "location" : { 
      "lat" : 23.181467, 
      "lng" : 79.98640709999999 
     }, 
     "location_type" : "APPROXIMATE", 
     "viewport" : { 
      "northeast" : { 
      "lat" : 23.246354, 
      "lng" : 80.08003219999999 
      }, 
      "southwest" : { 
      "lat" : 23.1050362, 
      "lng" : 79.85747339999999 
      } 
     } 
     }, 
     "place_id" : "ChIJfam2DxqugTkRueNDvBYGAkQ", 
     "types" : [ "locality", "political" ] 
    } 
    ], 
    "status" : "OK" 
}

和我的代碼：

<!DOCTYPE html> 
<html lang="en"> 
<head> 
    <meta charset="UTF-8"> 
    <title>Geocode</title> 
</head> 
<body> 
Enter Address<input type="text" id="UserInput"> 
Go<input type="button" onclick="geoCode()"> 

<script> 

    function geoCode(){ 

     var UserInput = document.getElementById('UserInput').valueOf(); 
     var xmlhttp = new XMLHttpRequest(); 
     var ApiKey = 'AIzaSyDZP2E_5LLE6VOwIbrNImS32sAx5rsgEbU'; 
     var myArr; 

     var url = 'https://maps.googleapis.com/maps/api/geocode/json?address='+UserInput.value+'&key='+ApiKey; 

     var xhr = new XMLHttpRequest(); 
     xhr.open('GET',url,true); 
     xhr.send(); 

     xhr.onreadystatechange = processRequest; 

     function processRequest() { 
      if(xhr.readyState==4 && xhr.status==200) 
      { 
       var response = JSON.parse(xhr.responseText); 
       alert(response["results"][0][0]); 
      } 
     } 
    }

我試圖JSON.stringify()但它從響應吐出來的所有數據。我如何從JSON中選擇一個特定的元素？請幫助

來源

2016-08-27 Jayant Usrete

'response [「results」] [0]'不是一個數組，所以''response [「results []] [0]'是'undefined'。你想要什麼？ – Leo

由於此函數用於將JSON的字符串表示形式轉換爲JSON對象，因此您不應該解析（JSON.parse）接收到的響應，您的情況已經以該形式出現。你需要的是通過它的路徑來訪問元素，像'result [0] .formatted_address'將返回''Jabalpur，Madhya Pradesh 482001，India'''。 – FDavidov

<!DOCTYPE html> 
<html lang="en"> 
<head> 
    <meta charset="UTF-8"> 
    <title>Geocode</title> 
</head> 
<body> 
Enter Address<input type="text" id="UserInput"> 
Go<input type="button" onclick="geoCode()"> 

<script> 

    function geoCode(){ 

     var UserInput = document.getElementById('UserInput').valueOf(); 
     var xmlhttp = new XMLHttpRequest(); 
     var ApiKey = 'AIzaSyDZP2E_5LLE6VOwIbrNImS32sAx5rsgEbU'; 
     var myArr; 

     var url = 'https://maps.googleapis.com/maps/api/geocode/json?address='+UserInput.value+'&key='+ApiKey; 

     var xhr = new XMLHttpRequest(); 
     xhr.open('GET',url,true); 
     xhr.send(); 

     xhr.onreadystatechange = processRequest; 

     function processRequest() { 
      if(xhr.readyState==4 && xhr.status==200) 
      { 
       var response = JSON.parse(xhr.responseText); 
       alert(response.results[0].geometry.location.lat + " " + response.results[0].geometry.location.lng); 
      } 
     } 
    }

來源

2016-08-27 10:01:34

使用javascript返回JSON解析[對象對象]

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