捕獲段落中的所有問題

Question

我一直在嘗試使用Javascript的RegEx解析給定段落中的每個問題。但是，我越來越不想要的結果：

的Javascript

regex = /(\S.+?[.!?])(?=\s+|$)/g; 
result = regex.exec("I can see you. Where are you? I am here! How did you get there?"); 

預期結果

["Where are you?", "How did you get there?"] 

實際結果

["I can see you.", "I can see you."] 

PS：如果有更好的方法來做到這一點，我就是耳朵！

Answer 1

試試這個：

var x = string.match(/\(?[A-Z][^\.!\?]+[!\.\?]\)?/g); 
x.filter(function(sentence) { 
    return sentence.indexOf('?') >= 0; 
}) 

Answer 2

JavaScript的正則表達式選項的.exec方法只返回與捕獲的第一場比賽。它還使用匹配字符串中的位置更新正則表達式對象。這就是允許你使用.exec方法遍歷一個字符串（以及爲什麼你只能獲得第一個匹配）。

嘗試使用字符串對象的.match方法代替：

regex = /(\S.+?[.!?])(?=\s+|$)/g; 
result = ("I can see you. Where are you? I am here! How did you get there?").match(regex); 

這給出了預期的結果：

[ 
    "I can see you.", 
    "Where are you?", 
    "I am here!", 
    "How did you get there?" 
] 

Answer 3

regex =/?([^.!]*)\?/g; 
text = "I can see you. Where are you? I am here! How did you get there?"; 
result = []; 
while (m = regex.exec(text)) { 
    result.push(m[1]) 
} 

輸出：

[ 'Where are you?', 
    'How did you get there?' ]