如何將HttpGet轉換爲HttpPost？

Question

我正在使用HttpGet方法從我的Android應用程序中從Web服務中檢索數據。任何人都可以告訴我如何將下面給出的代碼轉換爲HttpPost方法？

String url = URLEditor.encode("http://"+Constants.strURL+"Orders.asmx/CheckWebConnection?TechCode="+username+"&TechPIN="+password); 
    HttpClient httpClient = new DefaultHttpClient(); 
    HttpGet httpGet = new HttpGet(url); 
    response = httpClient.execute(httpGet); 
    HttpEntity entity = response.getEntity(); 
    if(entity == null) return false; 
    is = entity.getContent(); 

在此先感謝...

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感謝幫助我..

我試着用上面給出的代碼。但是我將Document對象作爲NULL。這是代碼

HttpClient httpClient = new DefaultHttpClient(); 
    HttpPost httpPost = new HttpPost("http://"+Constants.strURL+"Orders.asmx/CheckWebConnection"); 
    List<NameValuePair> nvpList = new ArrayList<NameValuePair>(); 
    nvpList.add(new BasicNameValuePair("TechCode", techcode)); 
    nvpList.add(new BasicNameValuePair("TechPIN", techpin)); 
    httpPost.setEntity(new UrlEncodedFormEntity(nvpList)); 
    HttpResponse response = httpClient.execute(httpPost); 
    HttpEntity entity = response.getEntity(); 
    InputStream is = entity.getContent(); 
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
    DocumentBuilder db = dbf.newDocumentBuilder(); 
    Document doc = db.parse(is); 

我將doc作爲NULL。當我使用HttpGet時沒有問題。它如何解決？請幫忙

Answer 1

這是代碼，這會幫助你。

ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); 
    nameValuePairs.add(new BasicNameValuePair("TechCode",username)); 
    nameValuePairs.add(new BasicNameValuePair("TechPIN",password)); 
try{ 
    HttpClient httpclient = new DefaultHttpClient(); 
    HttpPost httppost = new HttpPost("http://"+Constants.strURL+"Orders.asmx/CheckWebConnection"); 
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
    HttpResponse response = httpclient.execute(httppost); 
    HttpEntity entity = response.getEntity(); 
    is = entity.getContent(); 
    }catch(Exception e){ 
    Log.e("log_tag", "Error in http connection"+e.toString()); 
    }