1
可以someboby請幫助我這個查詢。 Basicall我知道如何連接表Zend框架,但我無法弄清楚是開始「AND ......」多數民衆贊成在我開始我subquery.My查詢是這樣zend框架查詢
SELECT requests.`email`,requests.`title`, `request_category`.`request_category_name`,
`request_route_category`.`department_id`,`departments`.`department_name`
FROM requests
JOIN `request_category` ON requests.`requests_category_id` = request_category.`request_category_id`
JOIN `request_route_category` ON `request_category`.`path_id` = `request_route_category`.`path_id`
JOIN `departments` ON `request_route_category`.`department_id` = `departments`.`department_id`
AND (SELECT `department_id`
FROM `request_route_category`
WHERE `request_route_category`.`department_id`=`departments`.`department_id`
AND `request_route_category`.`is_complete`=0
LIMIT 1)=7
最後一部分
我有這個現在
$select=$this->select()
->setIntegrityCheck(false)
->from($this->_name,array('reqemail'=>'email','reqcreated'=>'created'))
->join('request_category', 'requests.requests_category_id=request_category.request_category_id',array('catpath'=>'path_id','catid'=>'request_category.request_category_id','catname'=>'request_category_name'))
->join('request_route_category', 'request_category.path_id=request_route_category.path_id',array())
->join('departments','request_route_category.department_id=departments.department_id');
你可以發佈你現在或者你已嘗試什麼什麼? – Marcin 2011-05-08 10:41:26
@jamon我的意思是如果你可以發佈你的zend_db_select。你寫道,你知道如何進行連接,所以我假設你至少有部分zend_db_select用於這個查詢。 – Marcin 2011-05-08 11:01:02
@Marcin我已經包括了我現在請看看 – ngunjirimacharia 2011-05-08 11:19:01