我需要迭代錨標記中對象數組的對象。以下是我的代碼的格式對象數組的對象的迭代Angular4
{"1":{"uri":"test1","name":"test1","icon":"http:\/\/dummyurl\/images\/icons\/test1-icon.png","application_id":1},"2":{"uri":"test2","name":"test2","icon":"http:\/\/dummyurl\/images\/icons\/test2-icon.png","application_id":2},"3":{"uri":"test3","name":"test3","icon":"http:\/\/dummyurl\/images\/icons\/test3-icon.png","application_id":3},"4":{"uri":"test4","name":"test4","icon":"http:\/\/dummyurl\/images\/icons\/test4-icon.gif","application_id":4},"5":{"uri":"test5","name":"test5","icon":"http:\/\/dummyurl\/images\/icons\/test5-icon.png","application_id":5}}
的.ts文件
this.applicationService.getApplication(id)
.subscribe(applications => {
this.applications = applications.response;});
HTML
<a class="dropdown-item" href="#" NgForOf=" let obj of applications">
{{obj.name}} </a>
我被困在這個從去年3-4小時。任何幫助將不勝感激。
採取格式化你的代碼,並在發佈前正確提問的時間。此外,你還沒有解釋什麼不適用於你發佈的代碼或你做了什麼來解決它,或者你確切的困惑是什麼。 – csmckelvey
鑰匙是連續的數字? – alehn96