jQuery的.find()方法 - 字符串中搜索轉換爲jQuery對象
var myHTML = '<div class="mapInfoWindow"><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p></div><div class="mapInfoWindow"><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p></div><div class="mapInfoWindow"><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p><p class="infoWindowParagraph">DATA HERE</p></div>';
var obj = $(myHTML).get(0);
var totalCount = $(obj).find('.infoWindowParagraph').length;
console.log('Total p.infoWindowParagraph tags in the FIRST mapInfoWindow div is : ' + totalCount);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
所以我有一個HTML字符串,它是類似於以下,和我想要得到的計數.infoWindowParagraph
標籤在第一個.mapInfoWindow
div。無論出於何種原因,這不是我所期望的,我不知道爲什麼。
HTML
<div class="mapInfoWindow">
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
</div>
<div class="mapInfoWindow">
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
</div>
<div class="mapInfoWindow">
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
<p class="infoWindowParagraph">DATA HERE</p>
</div>
的jQuery/JavaScript的
var testObj = $([string from above]);
console.log(testObj.find('.mapInfoWindow').find('.infoWindowParagraph').length);
-- returns 0 every time should return 4
-- also tried below trying to focus on first index (first instance of mapInfoWindow div in object returned)
var testObj = $([string from above]).get(0).find('.infoWindowParagraph').length);
-- still returns 0
更新
那麼該死的,我現在的工作。對不起,在這裏浪費時間,忽略了明顯的!
我猜測錯誤可能與'$([字符串從上面])',能否請你張貼的選擇和請多一些周圍的HTML請? – Hodrobond
如果你這樣做,你可以在飛行中創建一個StackSnippet ... –
@Hodrobond - 我在我的問題中的一個JavaScript變量的HTML字符串,我簡單地使用$(myvariable)從該變量創建jQuery對象。 ; – Phil