2016-12-29 63 views
5

我試圖更新所有列與Json_Modify值:SQL Server JSON_Modify,如何更新所有?

DECLARE @JSON NVARCHAR(MAX) 
SET @JSON = 
N'{ 
"A":1, 
"TMP": [  
    {"A":"VALUE1", "B": "VALUE2", "C": 1}, 
    {"A":"VALUE3", "B": "VALUE4", "C": 2}, 
    {"A":"VALUE5", "B": "VALUE6", "C": 3}]} 
' 

SET @JSON = JSON_MODIFY(@JSON, '$.TMP.A', 'JEJE') 

SELECT * FROM OPENJSON(@JSON, '$.TMP') WITH (A NCHAR(10), B NCHAR(10), C INT) 

我需要更新所有列「A」與「傑傑奧」爲例,它無法正常工作。

回答

3

這裏有兩個選項。免責聲明:我不是通過SQL Server 2016在JSON的專業人士,但我已經砍了一些東西在一起。

選項1:您明確從JSON字符串創建結果集。爲什麼不創建結果集,然後更新它?

DECLARE @jsontable TABLE (A varchar(50), b varchar(50), c varchar(50)) 
DECLARE @JSON NVARCHAR(MAX) 

SET @JSON = 
N'{ 
"A":1, 
"TMP": [  
    {"A":"VALUE1", "B": "VALUE2", "C": 1}, 
    {"A":"VALUE3", "B": "VALUE4", "C": 2}, 
    {"A":"VALUE5", "B": "VALUE6", "C": 3}]} 
' 

--SET @JSON = JSON_MODIFY(@JSON, '$.TMP.A', 'JEJE') 
INSERT INTO @jsontable (a,b,c) 
SELECT * FROM OPENJSON(@JSON, '$.TMP') WITH (A NCHAR(10), B NCHAR(10), C INT) 

UPDATE @jsontable 
SET a = 'JEJE' 

SELECT * 
FROM @jsontable 

選項2:您可以操縱JSON組件,但必須將索引傳遞給函數。

DECLARE @JSON NVARCHAR(MAX) 
SET @JSON = 
N'{ 
"A":1, 
"TMP": [  
    {"A":"VALUE1", "B": "VALUE2", "C": 1}, 
    {"A":"VALUE3", "B": "VALUE4", "C": 2}, 
    {"A":"VALUE5", "B": "VALUE6", "C": 3}]} 
' 

SET @JSON = JSON_MODIFY(@JSON, '$.TMP[0].A', 'JEJE') 
SET @JSON = JSON_MODIFY(@JSON, '$.TMP[1].A', 'JEJE') 
SET @JSON = JSON_MODIFY(@JSON, '$.TMP[2].A', 'JEJE') 

SELECT * FROM OPENJSON(@JSON, '$.TMP') WITH (A NCHAR(10), B NCHAR(10), C INT) 
+0

謝謝,我想我會保存到表格,並在更新後這.. – mdelphi