將結果集轉換爲java中的嵌套json

Question

我想將結果集轉換爲Java中的JSON字符串。該數據的格式爲

+---+----------+-------------+---------------+ 
| id| job_type | question | response_type | 
+---+----------+-------------+---------------+ 
| 1 | quote | question1 | text1   | 
| 2 | quote | question2 | number2  | 
+---+----------+-------------+---------------+ 
| 3 | standard | question1 | text2   | 
| 4 | standard | question2 | number2  | 
+---+----------+-------------+---------------+ 

，我想在表單，以獲得JSON

{ 
    "JobType": 「Quote", 
    "Questions": [{ 
     "question": 「question1", 
     "response_type": 「 text1", 
    }, { 
     "question": 「question2", 
     "response_type": 「 number2", 
    }], 
    「JobType」:」Standard」, 
    "Questions": [{ 
     "question": 「question1", 
     "response_type": 「 number2", 
    }, { 
     "question": 「question2", 
     "response_type": 「 number2", 
    }] 
} 

這是我走到這一步，

JSONObject jobType = new JSONObject(); 
List<JSONObject> jobTypeQuestionListIndividual = new ArrayList<JSONObject>(); 

int i = 0; 
if (!jobTemplate.next()) {  
     System.out.println("No records found"); 
} else { 
    do { 
     if (i % 2 == 0) { 
      jobType.put("JobType",jobTemplate.getString("JobType")); 

      JSONObject firstQuestion = new JSONObject(); 
      firstQuestion.put("question", jobTemplate.getString("question")); 
      firstQuestion.put("response_type", jobTemplate.getString("response_type")); 

      jobTypeQuestionListIndividual.add(firstQuestion); 

      jobType.put("Questions",jobTypeQuestionListIndividual); 

     } else { 
      JSONObject question = new JSONObject(); 

      question.put("question", jobTemplate.getString("question")); 
      question.put("response_type", jobTemplate.getString("response_type")); 

      jobTypeQuestionListIndividual.add(question); 
     } 

     i = i+1; 

    } while (jobTemplate.next()); 
} 

System.out.println(jobType); 

但這會導致

{ 
    "JobType": 「Quote", 
    "Questions": [{ 
     "question": 「question1", 
     "response_type": 「 text1", 
    }, { 
     "question": 「question2", 
     "response_type": 「 number2", 
    },{ 
     "question": 「question1", 
     "response_type": 「 number2", 
    }, { 
     "question": 「question2", 
     "response_type": 「 number2", 
    }] 
} 

在此先感謝您的幫助頁。

Answer 1

我設法弄清楚如何通過首先創建hashmaps和hashsets來構建嵌套的json。這個靈感來自於如下回答： How to get an array of two values from jdbc result set和Storing a hash map inside another hash map and improving performance

我的代碼不正是我最初所需要的格式提供JSON，但它爲我工作。我得到

{「Quote」：[{「question」：「question1」，「response_type」：「text1」，}，{「question」：「question2」，「response_type」：「number2」，}]] 「標準」：[{ 「問題」：「問題1" ，「}]}

我更新的代碼是

String out = ""; 
try { 
    String jobType = ""; 
    ResultSet jobTemplate = jobs.getAllJobDetailsTemplate(Integer.parseInt(customerId)); 
    Map<String, Set<HashMap<String,String>>> jobTypes = new HashMap<String, Set<HashMap<String,String>>>(); 

    while (jobTemplate.next()) { 
     jobType = jobTemplate.getString("JobType"); 
     Set<HashMap<String,String>> questions = jobTypes.containsKey(jobType) ? jobTypes.get(jobType) : new HashSet<HashMap<String,String>>(); 
      HashMap<String,String> individualQuestion = new HashMap<String,String>(); 
      individualQuestion.put("question", jobTemplate.getString("question")); 
      individualQuestion.put("response_type", jobTemplate.getString("response_type")); 
      questions.add(individualQuestion); 
     jobTypes.put(jobType, questions); 
    } 

    out = new ObjectMapper().writeValueAsString(jobTypes); 
}