2017-03-03 256 views
0

我相當堅持這些幾天,我使用android應用程序來控制連接到arduino uno的電機,我可以建立連接併發送數據,但問題是,它對可以響應按鈕的響應有多少限制,有時它不能準確執行命令。 這是Arduino的使用android應用程序,arduino和esp8266 wifi模塊發送和接收數據

void loop() 
    { 
    if(esp8266.available()) // check if the esp is sending a message 
    { 
    Serial.println("Something received"); 
    delay(50); 
    if(esp8266.find("+IPD,")) 
    { 
     String action; 
     Serial.println("+IPD, found"); 
     int connectionId = esp8266.read()-48; // subtract 48 because the read() function returns 
              // the ASCII decimal value and 0 (the first decimal number) starts at 48 
     Serial.println("connectionId: " + String(connectionId)); 

     esp8266.find("motor="); 
     char s = esp8266.read(); 
     delay(50); 
     //right 
     if(s=='1'){ 
      action = "Motor is turning right"; 
      digitalWrite(5,HIGH); 
      digitalWrite(6,LOW); 
      digitalWrite(9,LOW); 
      digitalWrite(10,HIGH); 
     } 
     else if(s=='0'){ 
      action = "Motor is stopping"; 
      digitalWrite(5,LOW); 
      digitalWrite(6,LOW); 
      digitalWrite(9,LOW); 
      digitalWrite(10,LOW); 
     } 

     //left 
     else if(s=='2'){ 
      action = "Motor is turning left"; 
      digitalWrite(5,LOW); 
      digitalWrite(6,HIGH); 
      digitalWrite(9,HIGH); 
      digitalWrite(10,LOW); 
     } 

     //forward 
     else if(s=='3'){ 
      action = "Motor is moving forward"; 
      digitalWrite(5,HIGH); 
      digitalWrite(6,LOW); 
      digitalWrite(9,HIGH); 
      digitalWrite(10,LOW); 
     } 

     //backward 
      else if(s=='4'){ 
      action = "Motor is moving backward"; 
      digitalWrite(5,LOW); 
      digitalWrite(6,HIGH); 
      digitalWrite(9,LOW); 
      digitalWrite(10,HIGH); 
     } 

     else{ 
      action = "Try another command"; 
     } 
     Serial.println(action); 
     sendHTTPResponse(connectionId, action); 

    } 
} 
} 
void sendHTTPResponse(int id, String content) 
{ 
    String response; 
    response = "HTTP/1.1 200 OK\r\n"; 
    response += "Content-Type: text/html; charset=UTF-8\r\n"; 
    response += "Content-Length: "; 
    response += content.length(); 
    response += "\r\n"; 
    response +="Connection: close\r\n\r\n"; 
    response += content; 

    String cmd = "AT+CIPSEND="; 
    cmd += id; 
    cmd += ","; 
    cmd += response.length(); 

Serial.println("--- AT+CIPSEND ---"); 
sendESP8266Cmdln(cmd, 50); 

Serial.println("--- data ---"); 
sendESP8266Data(response, 50); 

} 
void sendESP8266Cmdln(String cmd, int waitTime) 
{ 
    esp8266.println(cmd); 
    delay(waitTime); 
    clearESP8266SerialBuffer(); 
} 

void sendESP8266Data(String data, int waitTime) 
{ 
    esp8266.print(data); 
    delay(waitTime); 
    clearESP8266SerialBuffer(); 
} 

void clearESP8266SerialBuffer() 
{ 
    Serial.println("= clearESP8266SerialBuffer() ="); 
    while (esp8266.available() > 0) { 
    char a = esp8266.read(); 
    Serial.write(a); 

    } 
    Serial.println("=============================="); 
} 

代碼這是Android的

public class FeedTask extends AsyncTask<String, Void, String> { 

    @Override 
     protected String doInBackground(String... params) { 
      try { 
       //change IP to the IP you set in the ARDUINO 
       URL url = new URL("http://192.168.254.101/?" + params[0]); 
       HttpURLConnection connection = (HttpURLConnection) url.openConnection(); 

       BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream())); 
       StringBuilder result = new StringBuilder(); 
       String inputLine; 
       while ((inputLine = in.readLine()) != null) 
        result.append(inputLine).append("\n"); 

       in.close(); 
       connection.disconnect(); 
       return result.toString(); 
      } catch (IOException e) { 
       e.printStackTrace(); 
      } 
      return null; 
     } 
    } 

    public void Motion() { 

     Button right = (Button) findViewById(R.id.button_right); 
     Button left = (Button) findViewById(R.id.button_left); 
     Button forward = (Button) findViewById(R.id.button_forward); 
     Button backward = (Button) findViewById(R.id.button_backward); 
     Button led_on = (Button) findViewById(R.id.led_on); 
     Button led_off = (Button) findViewById(R.id.led_off); 


     right.setOnTouchListener(new OnTouchListener() { 

      @Override 
      public boolean onTouch(View v, MotionEvent event) { 
       if (event.getAction() == MotionEvent.ACTION_DOWN) { 
        TextView text = (TextView) findViewById(R.id.textView); 
        text.setText("Right"); 
        new FeedTask().execute("motor=1"); 

       } else if (event.getAction() == MotionEvent.ACTION_UP) { 
        TextView text = (TextView) findViewById(R.id.textView); 
        text.setText("Tap again"); 
        new FeedTask().execute("motor=0"); 
       } 

       return true; 
      } 
     }); 

的代碼,我也正在發送使用Arduino的回機器人的數據,但這些錯誤存在的,我不能繼續。我讀過的HTML有多少隻能處理的限制,所以我不會深究這一點。我通過查看串行窗口所發生的錯誤是「Accept-ecoding gzip」,有時會被「接收到的東西」卡住,並且不會響應稍後點擊的任何按鈕。

+1

您的問題,更是一個建築一個比純代碼。您連續打開和關閉每個命令的http連接,而不會導致請求之間的大量開銷和爭用條件。您可以使用處理程序編組您的請求,或者(更好地)使用websocket進行查看。 – mach

+0

我只是以另一種方式實現它可能使用okhttp,你可以指導我如何使它,我已經看到一個建立的連接,通過獲取字符串在網站上,但我需要的是在網站上添加數據和把它傳遞給arduino。 – John

+0

對不起,我正在研究它看起來像我只需要改變我的arduino程序,從android發送的數據是可讀的和令人難以置信的快速。 – John

回答

0

我有同樣的問題..在解決方案中,您可以在網頁上的固定時間(如10秒或20秒)後刷新頁面,以便您的緩衝區代碼刷新並正常工作。

代碼是:

<script type="text/javascript">  
    setInterval(page_refresh, 5*60000); //NOTE: period is passed in milliseconds 
</script> 
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