如何從python中的元組中提取單詞

Question

(0, u'0.559*"delivery" + 0.124*"area" + 0.018*"mile" + 0.016*"option" + 0.012*"partner" + 0.011*"traffic" + 0.011*"hub" + 0.011*"thanks" + 0.010*"city" + 0.009*"way"') 
(1, u'0.397*"package" + 0.073*"address" + 0.055*"time" + 0.047*"customer" + 0.045*"apartment" + 0.037*"delivery" + 0.031*"number" + 0.026*"item" + 0.021*"support" + 0.018*"door"') 
(2, u'0.190*"time" + 0.127*"order" + 0.113*"minute" + 0.075*"pickup" + 0.074*"restaurant" + 0.031*"food" + 0.027*"support" + 0.027*"delivery" + 0.026*"pick" + 0.018*"min"') 
(3, u'0.072*"code" + 0.067*"gps" + 0.053*"map" + 0.050*"street" + 0.047*"building" + 0.043*"address" + 0.042*"navigation" + 0.039*"access" + 0.035*"point" + 0.028*"gate"') 

如何從上述每個元組中提取前3個單詞（基於旁邊的數字）？

輸出應爲：

(0,delivery area mile) 
(1,package address time) 
(2,time order minute) 
(3, code gps map) 

Answer 1

我將：

• 根據" + "（正則表達式可被需要，如果的空間的數量而變化）根據係數的浮點值創建通過分裂元組（係數，值），則根據"*"
• 排序那些元組，保持最高3
• 降的係數並加入字符串（汽提的過程中引號）

在（絡合物）的一行：

l = [(0, u'0.124*"area" + 0.018*"mile" + 0.016*"option" + 0.012*"partner" + 0.011*"traffic" + 0.011*"hub" + 0.011*"thanks" + 0.559*"delivery" + 0.010*"city" + 0.009*"way"'), 
(1, u'0.073*"address" + 0.055*"time" + 0.397*"package" + 0.047*"customer" + 0.045*"apartment" + 0.037*"delivery" + 0.031*"number" + 0.026*"item" + 0.021*"support" + 0.018*"door"'), 
(2, u'0.190*"time" + 0.127*"order" + 0.113*"minute" + 0.075*"pickup" + 0.074*"restaurant" + 0.031*"food" + 0.027*"support" + 0.027*"delivery" + 0.026*"pick" + 0.018*"min"'), 
(3, u'0.047*"building" + 0.072*"code" + 0.067*"gps" + 0.053*"map" + 0.050*"street" + 0.043*"address" + 0.042*"navigation" + 0.039*"access" + 0.035*"point" + 0.028*"gate"')] 

result = [" ".join(x[1].strip('"') for x in sorted((e.split("*") for e in sl[1].split(" + ")),key=lambda x:float(x[0]),reverse=True)[:3]) for sl in l] 

print(result) 

結果：

['delivery area mile', 'package address time', 'time order minute', 'code gps map'] 

（請注意，我已經打亂了項目的順序測試_係數排序）

Answer 2

使用re.findall()和str.join()函數的溶液：

import re 

l = [ 
(0, u'0.559*"delivery" + 0.124*"area" + 0.018*"mile" + 0.016*"option" + 0.012*"partner" + 0.011*"traffic" + 0.011*"hub" + 0.011*"thanks" + 0.010*"city" + 0.009*"way"'), 
(1, u'0.397*"package" + 0.073*"address" + 0.055*"time" + 0.047*"customer" + 0.045*"apartment" + 0.037*"delivery" + 0.031*"number" + 0.026*"item" + 0.021*"support" + 0.018*"door"'), 
(2, u'0.190*"time" + 0.127*"order" + 0.113*"minute" + 0.075*"pickup" + 0.074*"restaurant" + 0.031*"food" + 0.027*"support" + 0.027*"delivery" + 0.026*"pick" + 0.018*"min"'), 
(3, u'0.072*"code" + 0.067*"gps" + 0.053*"map" + 0.050*"street" + 0.047*"building" + 0.043*"address" + 0.042*"navigation" + 0.039*"access" + 0.035*"point" + 0.028*"gate"') 
] 

result = [tuple([t[0], ' '.join(re.findall(r'"([a-z]+)"', t[1])[0:3])]) for t in l] 
print(result) 

輸出：

[(0, 'delivery area mile'), (1, 'package address time'), (2, 'time order minute'), (3, 'code gps map')]