我是自學php語言。我創建了用於在數據庫中插入數據和搜索數據的PHP代碼。我想用MySQL和PHP插入&搜索數據到數據庫。我使用WAMP服務器。最後,搜索功能正常工作,但插入功能不起作用。搜索功能是工作,但插入功能不工作在PHP
表
我在
Fatal error: Uncaught exception 'mysqli_sql_exception' with message '
PHP代碼的錯誤是:
if(isset($_POST['insert'])){
$data = getPosts();
$sql = "INSERT INTO users (id, fname, lname, age) VALUES ('$data[0]','$data[1],'$data[2]','$data[3]')";
$result= mysqli_query($connect,$sql);
if($result){
echo 'Insert is success.....';
}
else{
echo 'Insert is unsuccess';
}
}
function getPosts(){
$posts = array();
$posts[0] = $_POST['id'];
$posts[1] = $_POST['fname'];
$posts[2] = $_POST['lname'];
$posts[3] = $_POST['age'];
return $posts;
}
//Search
if(isset($_POST['search'])){
$data = getPosts();
$search_Query = "SELECT * FROM users WHERE id = $data[0]";
$search_Result = mysqli_query($connect, $search_Query);
if($search_Result)
{
if(mysqli_num_rows($search_Result))
{
while($row = mysqli_fetch_array($search_Result))
{
$id = $row['id'];
$fname = $row['fname'];
$lname = $row['lname'];
$age = $row['age'];
}
}
else{
echo 'No Data for this id';
}
}else{
echo 'Result Error';
}
}
的html代碼:
<form action="" method="post">
Enter Your Id: <input type="number" name="id" placeholder="Id" value="<?php echo $id;?>"><br><br>
Enter Your First Name: <input type="text" name="fname" placeholder="First Name" value="<?php echo $fname;?>"><br><br>
Enter Your Last Name:<input type="text" name="lname" placeholder="Last Name" value="<?php echo $lname;?>"><br><br>
Enter Your Age:<input type="number" name="age" placeholder="Age" value="<?php echo $age;?>"><br><br>
<div>
<input type = "submit" name="insert" value="Add">
<input type = "submit" name="search" value="Search">
</div>
</form>
任何人都可以幫助我嗎?感謝任何觀衆。
是不是ID自動增量列? – Whencesoever
請分享您的'用戶'表的表格結構。 –
嘗試使用預準備語句來避免sql注入。 – JYoThI