我試圖用圖標替換數據中的某些符號。正則表達式問題 - 雙匹配號碼
我目前的RegEx是/\{.+?\}|\+\d+|\−\d+|\{[T]}|X|(0:)*/
這實際上擊中了我擁有的每一個樣品。
一些樣品
+2 −2 {2}
等等等等
然而,它還可選配+2/+2
並用符號代替每個+2
爲 +2
。
現在,在我的每個示例中,我使用+2,但它可以是1-100(大多數爲1-10)中的任何數字。 我會發布Rails Helper
我用它來交換。我嘗試了約20個不同版本的[\+(0-9\/\+0-9)]
,其中包括一個txt2re建議 - ([-+]\\d+\/[-+]\\d+)
但我或者A)失去了工作效果B)沒有做任何事情。
我歡迎任何建議。將發佈3個確切的文本樣本,爲我的一些問題有看法。
例子
`+1: Tap target permanent. It doesn't untap during its controller's next untap step. −2: Draw a card for each tapped creature target player controls. −8: You get an emblem with "You have no maximum hand size" and "Whenever a card is put into your graveyard from anywhere, you may return it to your hand."`
+1,-8應該成爲一個圖標(也就是不正常的 - 。跡象,但更廣泛的不確定它的技術名稱的東西尋找到
Equipped creature gets +1/+1 for each color among permanents you control. As long as Conqueror's Flail is attached to a creature, your opponents can't cast spells during your turn. Equip {2}
的+ 1/+ 1是變體數目,但幾乎總是以這種格式但是,有時也可能是*/+1
或+1/*
。 - 不確定如何解決此
+2: Look at the top card of target player's library. You may put that card on the bottom of that player's library.
0: Draw three cards, then put two cards from your hand on top of your library in any order. −1: Return target creature to its owner's hand. −12: Exile all cards from target player's library, then that player shuffles his or her hand into his or her library.
這是問題的大部分樣本。
我的助手
def card_text_swap card
if card.nil?
return
else
pos_entries = (1..20).map do |i|
["+#{i}", "<br /><i class=\"ms ms-loyalty-up ms-loyalty-#{i}\"></i>"]
end.to_h
neg_entries = (1..20).map do |i|
["−#{i}", "<br /><i class=\"ms ms-loyalty-down ms-loyalty-#{i}\"></i>"]
end.to_h
power_tough = (1..20).map do |i|
["+#{i}/", "<span></span>"]
end.to_h
cost_entries = (1..20).map do |i|
["{#{i}}", "<i class=\"ms ms-#{i} ms-cost ms-shadow\"></i>"]
end.to_h
hash = { '{hw}' => '<span class="ms-half"><i class="ms ms-w ms-cost"></i></span>',
'{W}' => '<i class="ms ms-w ms-cost ms-shadow"></i>',
'{R}' => '<i class="ms ms-r ms-cost ms-shadow"></i>',
'{U}' => '<i class="ms ms-u ms-cost ms-shadow"></i>',
'{G}' => '<i class="ms ms-g ms-cost ms-shadow"></i>',
'{B}' => '<i class="ms ms-b ms-cost ms-shadow"></i>',
'{S}' => '<i class="ms ms-s ms-cost ms-shadow"></i>',
'{X}' => '<i class="ms ms-x ms-cost ms-shadow"></i>',
'X' => '<i class="ms ms-x ms-cost ms-shadow"></i>',
'{W/U}' => '<i class="ms ms-wu ms-split ms-cost"></i>',
'{W/B}' => '<i class="ms ms-wb ms-split ms-cost"></i>',
'{W/P}' => '<i class="ms ms-wp ms-cost ms-cost"></i>',
'{2/W}' => '<i class="ms ms-2w ms-split ms-cost"></i>',
'{U/B}' => '<i class="ms ms-ub ms-split ms-cost"></i>',
'{U/R}' => '<i class="ms ms-ur ms-split ms-cost"></i>',
'{U/P}' => '<i class="ms ms-up ms-cost ms-cost"></i>',
'{2/U}' => '<i class="ms ms-2u ms-split ms-cost"></i>',
'{B/R}' => '<i class="ms ms-br ms-split ms-cost"></i>',
'{B/G}' => '<i class="ms ms-bg ms-split ms-cost"></i>',
'{B/P}' => '<i class="ms ms-bp ms-cost ms-cost"></i>',
'{2/B}' => '<i class="ms ms-2b ms-split ms-cost"></i>',
'{R/G}' => '<i class="ms ms-rg ms-split ms-cost"></i>',
'{R/P}' => '<i class="ms ms-rp ms-cost ms-cost"></i>',
'{R/W}' => '<i class="ms ms-rw ms-split ms-cost"></i>',
'{2/R}' => '<i class="ms ms-2r ms-split ms-cost"></i>',
'{G/W}' => '<i class="ms ms-gw ms-split ms-cost"></i>',
'{G/B}' => '<i class="ms ms-gb ms-split ms-cost"></i>',
'{G/P}' => '<i class="ms ms-gp ms-cost ms-cost"></i>',
'{2/G}' => '<i class="ms ms-2g ms-split ms-cost"></i>',
'0:' => '<br /><i class="ms ms-loyalty-zero ms-loyalty-0"></i>',
'{T}' => '<i class="ms ms-tap"></i>',
'{P}' => '<i class="ms ms-tap"></i>',
'{C}' => '<i class="ms ms-c"></i>',
'\n' => '<br>'
}
cost_entries = cost_entries.merge(neg_entries)
cost_entries = cost_entries.merge(pos_entries)
cost_entries = cost_entries.merge(power_tough)
hash = hash.merge(cost_entries)
card.gsub(/\{.+?\}|\+\d+|\−\d+|\{[T]}|X|(0:)*|(\+[0-9]\/)/) { | k | hash[k] || k }.html_safe
end
end
雖然是Rails的具體的,它只是用於生成散列我,我再出來GSUB。
沒有MCVE,很難理解你需要什麼。試試'/[-+]\d+\/[-+]\d+|\{.+?\}|\+\d+|\-\d+|\{[T]}|X|(0:)* /'。然而,我不明白爲什麼你有'(0:)*'匹配任何空的位置之前不匹配的符號。 –
@WiktorStribiżew你是什麼意思?我提供了3個示例 - 其中一個失敗,每次我嘗試不同的變體。 您的解決方案實際上似乎工作。你會把它作爲答案與解釋,我會檢查一些其他卡片,並將其標記爲答案?謝謝。 – DNorthrup
好吧,我現在看到了這個問題,我發佈瞭解釋的答案。 –