2017-03-07 70 views
0

我的代碼:的Android的SQLite中刪除一行

public void droptablecontents(String category) 
{ 
    SQLiteDatabase db = this.getWritableDatabase(); 
    String query = "DELETE FROM " + Table_Name + " WHERE " + KEY_CAT + "=" + category; 
    Cursor cursor = db.rawQuery(query, null); 
    cursor.moveToFirst(); 
    cursor.close(); 
} 

我的表的創建語句:

"CREATE TABLE IF NOT EXISTS " + Table_Name + "(" + KEY_NOTE + " TEXT, " + KEY_CAT + " TEXT" + ")" 

我的日誌貓錯誤:

android.database.sqlite.SQLiteException: no such column: Ideas (code 1): , while compiling: DELETE FROM Cats WHERE cat=Ideas 

但爲什麼它尋找一個列命名爲'想法'?我正在嘗試在KEY_CAT列中搜索值'Ideas'。

+0

'String [] params = new String [] {contact_no}; Cursor c = db.rawQuery(「DELETE FROM + Table_Name +」WHERE「+ KEY_CAT +」=?「, params);' –

+0

**」從「+ Table_Name +」中刪除其中「+ KEY_CAT +」(「 +類別+「)」** 試試這個查詢 –

回答

-1

添加「'」爲條件,它是文本。

public void droptablecontents(String category) 
{ 
    SQLiteDatabase db = this.getWritableDatabase(); 
    String query = "DELETE FROM " + Table_Name + " WHERE " + KEY_CAT + "='" + category + "'"; 
    Cursor cursor = db.rawQuery(query, null); 
    cursor.moveToFirst(); 
    cursor.close(); 
} 
+0

當這個值包含一個報價時,這將會爆炸。 –