我一個邪惡的劊子手計劃出於某種原因,我得到這個工作的錯誤:邪惡的劊子手Java程序
What length word do you want to use? 4
How many wrong answers allowed? 4
guesses : 4
guessed : []
current : ----
Your guess? e
Exception in thread "main" java.lang.NullPointerException
at Game.HangmanManager.record(HangmanManager.java:142)
at Game.HangmanMain.playGame(HangmanMain.java:62)
at Game.HangmanMain.main(HangmanMain.java:42)
這裏是我的程序:
package Game;
import java.util.*;
public class HangmanManager
{
private String pattern;
private int max;
private int length;
private SortedSet<Character> guessesMade;
private Set<String> currentWords;
private Map<String, Set<String>> patternMap;
public HangmanManager(List<String> dictionary , int length, int max)
{
this.max = max;
this.length = length;
if(length < 1 && max < 0)
{
throw new IllegalArgumentException();
}
words = new TreeSet<String>();
guessesMade = new TreeSet<Character>();
currentWords = new TreeSet<String>(); // current words =(words)
patternMap = new TreeMap<String, Set<String>>(); // patternMAP = < pattern, words>
for (String word : dictionary)
{
if (word.length() == length)
{
words.add(word); // if length of the word matches a word with the same length it will be added
}
}
}
public Set<String> words()
{
return words;
}
public int guessesLeft()
{
return max - guessesMade.size();
}
public SortedSet<Character> guesses()
{
return guessesMade;
}
public String pattern()
{
if (words.isEmpty())
{
throw new IllegalArgumentException("Invalid No Words");
}
pattern = " "; // blank for now
for (int i = 0; i < length; i++)
{
pattern += "-"; // will have a "-" for how long the length of the word is
}
return pattern; // will return the number of lines
}
public int record(char guess)
{
if (guessesLeft() < 1 || words.isEmpty())
{
throw new IllegalStateException();
}
if (!words.isEmpty() && guessesMade.contains(guess))
{
throw new IllegalArgumentException();
}
guessesMade.add(guess); // guess
int occurences = 0;
for(String word: words)
{
if(patternMap.containsKey (pattern))
{
occurences = generatePattern(word, guess); // the word including the guess letter will fill in the blank spots
currentWords.add(word); // the word will be added to the possibilities
currentWords = patternMap.get(pattern); // the word will be able to fill once the guesses are made
// if(patternMap.get(pattern)!=null)
// {
// currentWords = patternMap.get(pattern);
//
// }
patternMap.put(pattern, currentWords);
}
else
{
currentWords.add(word);
patternMap.put(pattern, currentWords);
}
}
words = find();
return occurences;
}
private Set<String> find()
{
int maxSize = 0;
Map <String, Integer> patternCount = new TreeMap<String, Integer>();
for (String key : patternMap.keySet()) // keyset equals word
{
patternCount.put(key, patternMap.get(key).size()); // size of the word
if (patternMap.get(key).size() > maxSize)
{
maxSize = patternMap.get(key).size();
pattern = key; // pattern will becomes based on the word
} else if (patternMap.get(key).size() == maxSize)
{
if (key.length() >= pattern.length())
{
pattern = key;
maxSize = patternMap.get(key).size(); // the pattern is now the word key
}
}
}
System.out.println("Current pattern: " + pattern);
return patternMap.get(pattern); // the pattern that will becomes now that the word was picked
}
private int generatePattern(String s, char guess)
{
int count = 0;
pattern = "";
for (int i = 0; i < length; i++)
{
if (s.charAt(i) == guess)
{
pattern += guess + " ";
count++;
} else
{
pattern += "- ";
}
}
return count;
}
}
錯誤似乎發生在爲記錄方法:
patternMap.put(pattern, currentWords);
149線
我跑了調試器很多次,我注意到如果你遵循這個程序,你會發現currentWords在程序運行一遍之後最終會變成Null,儘管我實例化了它,並且我爲patternMap創建了一個Map。
如果誰能告訴我做什麼或改變什麼,我將非常感激,因爲我所以用這個
你的代碼是不完整的,並且將無法編譯,這意味着您的問題或者將要關閉爲[重複什麼是空指針異常,以及如何解決它?](http://stackoverflow.com/questions/218384/what-is-a-null-pointer-exception-and-how-do-i-fix-it)或「爲什麼我的代碼不工作 - 沒有提供可運行的示例「 – MadProgrammer
我可以提供HangmanMain程序和字典文本文件 – Jay