將4個變量組合成一個變量名！

Question

我不認爲這是正確的...

$compname = $subformat_$subgame_$subname_$subseason; 

什麼是正確的語法？ 感謝

Answer 1

grossvogel溶液是正確的。你可能也想知道這是件好事：

$compname = {$subformat.'_'.$subgame.'_'.$subname.'_'.$subseason}; 

但你要怎樣做看起來很奇怪...... 你爲什麼不使用四維陣列？

Answer 2

$compname = implode('_', array ($subformat,$subgame,$subname,$subseason)); 

或

$compname = sprintf("%s_%s_%s_%s", $subformat, $subgame, $subname, $subseason); 

或

$compname = "$subformat_$subgame_$subname_$subseason";