2012-08-07 262 views
1

如何搜索字符串值來查找字符串值?將字符串網址與字符串值進行比較

字符串URL:

http://localHost:8070/serviceCase=ActiveService 
http://localHost:8070/serviceCase=KoplService 

字符串值:

ActiveService 

我需要打印確實有 「主動服務」 的網址!

回答

1

你也許可以做這樣的事情(如果您的網址確實是一個字符串):

if ([url rangeOfString:value].location == NSNotFound){ 
    dosomething 
} else { 
    doSomethingElse 
} 
0
if([string hasSuffix:@"ActiveService"]) { 
      // Do your stuff 
} 
0
NSString *url = @"http://localHost:8070/serviceCase=ActiveService"; 

if ([url rangeOfString:@"ActiveService"].location != NSNotFound) { 
    NSLog(@"URL has the string"); 
} 
0

我推薦下面的NSString類別。

NSString+Extend.h

#import <Foundation/Foundation.h> 

@interface NSString (Extend) 
- (BOOL)containsString:(NSString *)aString ignoringCase:(BOOL)flag; 
- (BOOL)containsString:(NSString *)aString; 
@end 

NSString+Extend.m

#import "NSString+Extend.h" 

@implementation NSString (Extend) 
- (BOOL)containsString:(NSString *)aString 
{ 
    return [self containsString:aString ignoringCase:NO]; 
} 

- (BOOL)containsString:(NSString *)aString ignoringCase:(BOOL)flag 
{ 
    unsigned mask = (flag ? NSCaseInsensitiveSearch : 0); 
    return [self rangeOfString:aString options:mask].length > 0; 
} 
@end 

#import "NSString+Extend.h" 

NSString *url = @"http://localHost:8070/serviceCase=ActiveService"; 
NSString *findString = @"ActiveService"; 

BOOL isContains = [url containsString:findString]; 
if(isContains) 
{ 
    //do stuff 
} 
else 
{ 
    //do stuff 
} 
+0

這是一個很好的解決方案,但它確實取決於必須做字符串比較的數量。如果我們只是談論代碼中的幾個地方,我認爲你的解決方案有點矯枉過正。 – Jesper 2012-08-07 11:50:32

+0

我知道。但是,當我測試性能比較rangeOfString沒有OverKill。當稍後使用KMP算法時,我將創建類別。 – 2012-08-07 11:55:43

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