日曆代奇怪的失敗

Question

我着手生成一個數組，其中包含從此（現在）月份開始的12個月日曆。這是針對特定的應用程序，並且需要特殊的代碼，所以我不能使用日曆庫。

這裏是我的代碼：

header('Content-type: text/plain'); 

$Cal1 = array(); 

$now = new fTimestamp('now'); 
$now = $now->modify('Y-m-1 00:00:00'); 

for ($i = 0; $i < 12; $i++) { 
if ($i > 1) { 
    $then = $now->adjust("+$i months"); 
} 
elseif ($i == 1) { 
    $then = $now->adjust("+1 month"); 
} 
else { 
    $then = $now; 
} 
$thisMonth = $then->format('F'); 
$Cal1[$thisMonth] = array(); 
$thisMonthDays = $then->format('t'); 
for ($j = 0; $j < $thisMonthDays; $j++) { 
    if ($i > 1) { 
    $then = $then->adjust("+$i days"); 
    } 
    elseif ($i == 1) { 
    $then = $then->adjust("+1 day"); 
    } 
    $thisDate = $then->format('j'); 
    $thisDay = $then->format('l'); 
    $Cal1[$thisMonth][$thisDate] = $thisDay; 
} 
} 

var_dump($Cal1); 

這應該生成一種形式的數組：

array { 
    ["Month_Name"] => array { 
     [Day_Number] => "Day_Name" 
     etc... 
    } 
    etc... 
} 

的腳本輸出月份的正確數量，而不是幾天的權數。 ..全部轉儲非常冗長，所以我只會發布10月，2月和3月：

array(12) { 
    ["October"]=> 
    array(1) { 
    [1]=> 
    string(6) "Friday" 
    } 
    ["February"]=> 
    array(22) { 
    [5]=> 
    string(8) "Saturday" 
    [9]=> 
    string(9) "Wednesday" 
    [13]=> 
    string(6) "Sunday" 
    [17]=> 
    string(8) "Thursday" 
    [21]=> 
    string(6) "Monday" 
    [25]=> 
    string(6) "Friday" 
    [1]=> 
    string(7) "Tuesday" 
    [29]=> 
    string(7) "Tuesday" 
    [2]=> 
    string(8) "Saturday" 
    [6]=> 
    string(9) "Wednesday" 
    [10]=> 
    string(6) "Sunday" 
    [14]=> 
    string(8) "Thursday" 
    [18]=> 
    string(6) "Monday" 
    [22]=> 
    string(6) "Friday" 
    [26]=> 
    string(7) "Tuesday" 
    [30]=> 
    string(8) "Saturday" 
    [4]=> 
    string(9) "Wednesday" 
    [8]=> 
    string(6) "Sunday" 
    [12]=> 
    string(8) "Thursday" 
    [16]=> 
    string(6) "Monday" 
    [20]=> 
    string(6) "Friday" 
    [24]=> 
    string(7) "Tuesday" 
    } 
    ["March"]=> 
    array(19) { 
    [6]=> 
    string(6) "Sunday" 
    [11]=> 
    string(6) "Friday" 
    [16]=> 
    string(9) "Wednesday" 
    [21]=> 
    string(6) "Monday" 
    [26]=> 
    string(8) "Saturday" 
    [31]=> 
    string(8) "Thursday" 
    [5]=> 
    string(8) "Thursday" 
    [10]=> 
    string(7) "Tuesday" 
    [15]=> 
    string(6) "Sunday" 
    [20]=> 
    string(6) "Friday" 
    [25]=> 
    string(9) "Wednesday" 
    [30]=> 
    string(6) "Monday" 
    [4]=> 
    string(6) "Monday" 
    [9]=> 
    string(8) "Saturday" 
    [14]=> 
    string(8) "Thursday" 
    [19]=> 
    string(7) "Tuesday" 
    [24]=> 
    string(6) "Sunday" 
    [29]=> 
    string(6) "Friday" 
    [3]=> 
    string(9) "Wednesday" 
    } 

現在，這是怎麼回事？

Answer 1

並不直接回答你的問題，但我會做了很多簡單的，像這樣：

$cursor = mktime(0, 0, 0, date('m'), 1); 
$end = strtotime('+1 year', $cursor); 

$out = array(); 

while ($cursor < $end) { 
    $out[date('F', $cursor)][date('j', $cursor)] = date('l', $cursor); 
    $cursor = strtotime('+1 day', $cursor); 
} 

var_dump($out); 

直接回答你的問題，你$then相對總是調整到自己與越來越大的數字，因此你正在跳過幾天，並且正在變得時髦。

for ($j = 1; $j < $thisMonthDays; $j++) { 
    $then = $then->adjust("+$i days"); 
} 

1. $then是第一，添加1（第一次迭代）
2. $then是第二，添加2（第二次迭代）
3. $then是第四，添加3
4. $then是第7位，你加4
5. etc。