算法將1轉換爲「一」等在objective-c

Question

我正在尋找一種算法或函數來分別將整數0,1,2轉換爲零，一，二。我們如何在Objective-C中做到這一點？

Answer 1

Apple爲許多數據類型內置了許多方便的格式化功能。稱爲「格式化程序」，他們可以將對象轉換爲字符串表示或從字符串表示轉換對象。

對於您的情況，您將使用NSNumberFormatter，但是如果您有一個整數，則需要先將其轉換爲NSNumber。看下面的例子。

NSInteger anInt = 11242043; 
NSString *wordNumber; 

//convert to words 
NSNumber *numberValue = [NSNumber numberWithInt:anInt]; //needs to be NSNumber! 
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init]; 
[numberFormatter setNumberStyle:NSNumberFormatterSpellOutStyle]; 
wordNumber = [numberFormatter stringFromNumber:numberValue]; 
NSLog(@"Answer: %@", wordNumber); 
// Answer: eleven million two hundred forty-two thousand forty-three 

Answer 2

這是我的代碼爲0到100（您可以根據您的要求更新）。完美的工作！

-(NSDictionary *)algorithm 
{ 
    NSArray *myArray = @[@"Zero",@"One",@"Two",@"Three",@"Four",@"Five",@"Six",@"Seven",@"Eight",@"Nine",@"Ten",@"Eleven",@"Twelve",@"Thirteen",@"Fourteen",@"Fifteen",@"Sixteen",@"Sevteen",@"Eighteen",@"Nineteen"]; 

    NSArray *tensArray = @[@"Twenty",@"Thirty",@"Fourty",@"Fifty",@"Sixty" 
          ,@"Seventy",@"Eighty",@"Ninety",@"One Hundred"]; 

    NSMutableDictionary *numberStringDictionary = [[NSMutableDictionary alloc] init]; 

    NSMutableArray *numberStringsArray = [[NSMutableArray alloc] init]; 

    for(int i=0;i<=100;i++) 
    { 

     if(i<20) 
     { 
      [numberStringDictionary setObject:myArray[i] forKey:[NSString stringWithFormat:@"%d",i]]; 
      [numberStringsArray addObject:myArray[i]]; 
      NSLog(@"\n%@",myArray[i]); 
     } 
     else if(i%10==0) 
     { 
      [numberStringDictionary setObject:tensArray[i/10-2] forKey:[NSString stringWithFormat:@"%d",i]]; 
      [numberStringsArray addObject:tensArray[i/10-2]]; 
      NSLog(@"\n%@",tensArray[i/10-2]); 
     } 
     else 
     { 
      [numberStringDictionary setObject:[NSString stringWithFormat:@"%@ %@",tensArray[i/10-2],myArray[i%10]] forKey:[NSString stringWithFormat:@"%d",i]]; 

      [numberStringsArray addObject:[NSString stringWithFormat:@"%@ %@",tensArray[i/10-2],myArray[i%10]]]; 

      NSLog(@"%@",[NSString stringWithFormat:@"%@ %@",tensArray[i/10-2],myArray[i%10]]); 
     } 

    } 
    return numberStringDictionary; 
}