我怎麼可以在SQL

拆分列值到不同的列我有臺試驗作爲我怎麼可以在SQL

col_1 
---------- 
aa,ab,ac 
ba,bb,bc 
ca,cb,cc

我想輸出

col_1  col_2 col_3 
------------------------- 
aa  ab  ac 
ba  bb  bc 
ca  cb  cc

來源

2012-07-10 Harsh Patel

該列是否總是隻包含3個兩個字符組？ – 2012-07-10 07:01:42

declare @T table 
(
    col_1 varchar(100) 
) 

insert into @T values 
('aa,ab,ac,4,5,6,7,8,9,10'), 
('ba,bb,bc,4,5,6,7,8,9,10'), 
('ca,cb,cc,4,5,6,7,8,9,10') 

select left(T.col_1, C1.Pos-1) as col_1, 
     substring(T.col_1, C1.Pos+1, C2.Pos-C1.Pos-1) as col_2, 
     substring(T.col_1, C2.Pos+1, C3.Pos-C2.Pos-1) as col_3, 
     substring(T.col_1, C3.Pos+1, C4.Pos-C3.Pos-1) as col_4, 
     substring(T.col_1, C4.Pos+1, C5.Pos-C4.Pos-1) as col_5, 
     substring(T.col_1, C5.Pos+1, C6.Pos-C5.Pos-1) as col_6, 
     substring(T.col_1, C6.Pos+1, C7.Pos-C6.Pos-1) as col_7, 
     substring(T.col_1, C7.Pos+1, C8.Pos-C7.Pos-1) as col_8, 
     substring(T.col_1, C8.Pos+1, C9.Pos-C8.Pos-1) as col_9, 
     stuff(T.col_1, 1, C9.Pos, '') as col_10 
from @T as T 
    cross apply (select charindex(',', col_1)) as C1(Pos) 
    cross apply (select charindex(',', col_1, C1.Pos+1)) as C2(Pos) 
    cross apply (select charindex(',', col_1, C2.Pos+1)) as C3(Pos) 
    cross apply (select charindex(',', col_1, C3.Pos+1)) as C4(Pos) 
    cross apply (select charindex(',', col_1, C4.Pos+1)) as C5(Pos) 
    cross apply (select charindex(',', col_1, C5.Pos+1)) as C6(Pos) 
    cross apply (select charindex(',', col_1, C6.Pos+1)) as C7(Pos) 
    cross apply (select charindex(',', col_1, C7.Pos+1)) as C8(Pos) 
    cross apply (select charindex(',', col_1, C8.Pos+1)) as C9(Pos)

來源

2012-07-10 08:11:00

嘿，感謝您的答覆，但我有10個值與逗號分隔，那我該如何使用它？ – 2012-07-13 06:02:02

只需添加更多列。 – 2012-07-13 06:19:21

Hey thnx Mikael – 2012-07-13 08:46:35

select substring(col_1,1,CHARINDEX(',',col_1,1)-1) as col_1, 
substring(col_1,(CHARINDEX(',',col_1,1)+1),CHARINDEX(',',col_1,CHARINDEX(',',col_1,1)+1)-(CHARINDEX(',',col_1,1)+1)) as col_2, 
substring(col_1,CHARINDEX(',',col_1,CHARINDEX(',',col_1,1)+1)+1,LEN(col_1)) as col_3 
from test

來源

2012-07-10 07:15:57

'ROW_NUMBER（）over（order by（select 0））'不能保證爲相同的原始行生成相同的行號。 – 2012-07-10 07:42:47

@Damien_The_Unbeliever：同意你，謝謝..在幾分鐘內編輯我的答案 – 2012-07-10 07:47:17

@Damien_The_Unbeliever：我已經更新了我的查詢，請現在chaeck – 2012-07-10 07:56:16

您可以使用一個函數來split字符串和代碼將看起來像

選擇dbo.Split（col_1，'，'）從測試

來源

2012-07-10 07:40:23 Ankit

嗨，如果有固定的列數，那麼我們可以使用下面的查詢。

DECLARE @col TABLE(col_1 varchar(255)) 

INSERT INTO @col 
values('aa,ab,ac'),('ba,bb,bc'),('ca,cb,cc') 

select * from @col 

select LEFT(col_1,CHARINDEX(',',col_1,1)-1) as col_1, 
LEFT(RIGHT(col_1,len(col_1)-CHARINDEX(',',col_1,1)),CHARINDEX(',',RIGHT(col_1,len(col_1)-CHARINDEX(',',col_1,1)),1)-1) as col_2, 
RIGHT(col_1,2) as col_3 
from @col

來源

2012-07-10 11:30:21 AnandPhadke

即使超過2個字符用逗號分隔，以下是解決方案。

DECLARE @col TABLE(col_1 varchar(255)) 

INSERT INTO @col 
values('aa,ab,ac'),('ba,bb,bc'),('ca,cb,cc') 

select * from @col 

select LEFT(col_1,CHARINDEX(',',col_1,1)-1) as col_1, 
LEFT(RIGHT(col_1,len(col_1)-CHARINDEX(',',col_1,1)),CHARINDEX(',',RIGHT(col_1,len(col_1)-CHARINDEX(',',col_1,1)),1)-1) as col_2, 
RIGHT(RIGHT(col_1,len(col_1)-CHARINDEX(',',col_1,1)),LEN(RIGHT(col_1,len(col_1)-CHARINDEX(',',col_1,1)))-CHARINDEX(',',RIGHT(col_1,len(col_1)-CHARINDEX(',',col_1,1)),1)) as col_3 

from @col

來源

2012-07-10 11:38:49 AnandPhadke

我怎麼可以在SQL

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