2013-02-20 44 views
0
SELECT COUNT(1) 
FROM (CMEOWN.ird_no_preselection_1  AS t1 
INNER JOIN CMEOWN.ird_no_preselection_1_a AS t2 
ON t1.ird_number  = t2.ird_number 
AND t1.location_number = t2.location_number); 

我在做什麼錯在這裏?內連接缺少右括號。

回答

3

爲什麼不無paranthesis:

SELECT COUNT(1) 
FROM CMEOWN.ird_no_preselection_1  AS t1 
INNER JOIN CMEOWN.ird_no_preselection_1_a AS t2 
ON t1.ird_number  = t2.ird_number 
AND t1.location_number = t2.location_number; 

那就試試這個(刪除AS ES):

SELECT COUNT(1) 
FROM CMEOWN.ird_no_preselection_1 t1 
INNER JOIN CMEOWN.ird_no_preselection_1_a t2 
ON t1.ird_number  = t2.ird_number 
AND t1.location_number = t2.location_number; 
+0

這給了我 'SQL語句無法正常結束'。 – dwjohnston 2013-02-20 00:05:27

+0

@ user1068446檢查更新 – Andrey 2013-02-20 00:07:33

+0

謝謝。 abdefgh – dwjohnston 2013-02-20 00:09:24