1
SELECT * FROM reviews
WHERE id in (SELECT review_id FROM reviews_businesses_users_bridge WHERE user_id = 1)
Union
SELECT * FROM reviews
WHERE id in (select review_id FROMreviews_drivers_users_bridge WHERE user_id = 1);
此查詢完美地與工作臺的工作,但是當我在我的應用程序使用此查詢它給錯誤..執行復雜查詢
@Query(value = "SELECT * FROM reviews WHERE id in (SELECT review_id FROM reviews_businesses_users_bridge WHERE user_id = ?) Union SELECT * FROM reviews WHERE id in (select review_id FROM reviews_drivers_users_bridge WHERE user_id = ?)",nativeQuery = true)
List<Review> getAllReceivedReviewsByUserId(Long userId);
,並在日誌中的錯誤是「沒有找到處理程序法」,這不會使任何意義對我來說,因爲如果我讓喜歡
@Query(value = "SELECT * FROM reviews WHERE id in (SELECT review_id FROM reviews_businesses_users_bridge WHERE user_id = ?)",nativeQuery = true)
List<Review> getAllReceivedReviewsByUserId(Long userId);
查詢那麼它的工作完美,當我添加了一些更復雜則顯示錯誤。
post error may be? –
您在sql中只有一個參數'Long userId'和多個綁定變量佔位符。 –
yes..Thank你指出我的錯誤 –