2013-03-12 87 views
4

我試圖從我的SQLite數據庫檢索一些信息爲Android應用程序的登錄頁面。從一個數據庫中檢索的代碼是:參數化查詢拋出IllegalArgumentException:無法綁定參數

login.setOnClickListener(new OnClickListener() { 
     @Override 
     public void onClick(View v) { 
      SQLiteDatabase db = SQLiteDatabase.openDatabase("/data/data/com.example.androidproject/databases/myDB", null, 0); 
      // Check Login 
      String username = usernamelogin.getText().toString(); 
      String password = loginpassword.getText().toString(); 

      Cursor c = db.rawQuery("SELECT name, password FROM User WHERE name='?' AND password='?'", new String[] {username, password}); 
      if(c.moveToFirst()) { 
       Intent intent=new Intent(Login.this, MainActivity.class); 
       startActivity(intent); 
      } else { 
       Toast.makeText(getApplicationContext(), "Invalid", Toast.LENGTH_LONG).show(); 
      } 
      c.close(); 
      db.close(); 
     } 
    }); 

但我不斷收到此錯誤:

03-12 20:38:40.216: E/AndroidRuntime(691): FATAL EXCEPTION: main 
03-12 20:38:40.216: E/AndroidRuntime(691): java.lang.IllegalArgumentException: Cannot bind argument at index 2 because the index is out of range. The statement has 0 parameters. 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.database.sqlite.SQLiteProgram.bind(SQLiteProgram.java:212) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.database.sqlite.SQLiteProgram.bindString(SQLiteProgram.java:166) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.database.sqlite.SQLiteProgram.bindAllArgsAsStrings(SQLiteProgram.java:200) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.database.sqlite.SQLiteDirectCursorDriver.query(SQLiteDirectCursorDriver.java:47) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.database.sqlite.SQLiteDatabase.rawQueryWithFactory(SQLiteDatabase.java:1314) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.database.sqlite.SQLiteDatabase.rawQuery(SQLiteDatabase.java:1253) 
03-12 20:38:40.216: E/AndroidRuntime(691): at com.example.androiddiet.Login$2.onClick(Login.java:61) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.view.View.performClick(View.java:4084) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.view.View$PerformClick.run(View.java:16966) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.os.Handler.handleCallback(Handler.java:615) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.os.Handler.dispatchMessage(Handler.java:92) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.os.Looper.loop(Looper.java:137) 
03-12 20:38:40.216: E/AndroidRuntime(691): at android.app.ActivityThread.main(ActivityThread.java:4745) 
03-12 20:38:40.216: E/AndroidRuntime(691): at java.lang.reflect.Method.invokeNative(Native Method) 
03-12 20:38:40.216: E/AndroidRuntime(691): at java.lang.reflect.Method.invoke(Method.java:511) 
03-12 20:38:40.216: E/AndroidRuntime(691): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:786) 
03-12 20:38:40.216: E/AndroidRuntime(691): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553) 
03-12 20:38:40.216: E/AndroidRuntime(691): at dalvik.system.NativeStart.main(Native Method) 

回答

20

不要用引號括替換字符:

WHERE name=? AND password=? 

使用name='?'會嘗試比較name字面問號...

+0

是固定的問題!非常感謝你:) – hamod90 2013-03-12 20:49:25

+0

很高興能幫助,請點擊此答案中的複選標記以接受它作爲解決方案。 – Sam 2013-03-12 20:59:11

5

不回答你提出的問題,但你仍然沒有問過的問題......你正在UI線程上執行數據庫操作。絕對不是這樣做的,考慮使用AsyncTask來放置這個數據庫操作代碼而不是onClick。

2

我也有類似的錯誤。

問題是等號運算符周圍的空格。

通過從WHERE fieldName = ?的空間來WHERE fieldName=?