顯示下面的查詢用逗號分隔的列表

Question

我有以下查詢：

SELECT coalesce(COUNT('view_id'),0) level1count,y,m 
    from 
    (select 1 as m,2016 as y 
    union 
    select 2 as m,2016 as y 
    union 
    select 3 as m,2016 as y 
    union 
    select 4 as m,2016 as y 
    union 
    select 5 as m,2016 as y 
    union 
    select 6 as m,2016 as y 
    union 
    select 7 as m,2016 as y 
    union 
    select 8 as m,2016 as y 
    union 
    select 9 as m,2016 as y 
    union 
    select 10 as m,2016 as y 
    union 
    select 11 as m,2016 as y 
    union 
    select 12 as m ,2016 as y 
    ) months 
    left join page_views on(months.m = month(page_views.view_date) and months.y = year(page_views.view_date)) 
    group by months.m, year(page_views.view_date) 

導致以下：

level1count Year Month 
----------------------------------------- 
1    2016 1 
1    2016 2 
1    2016 3 
1    2016 4 
34    2016 5 
1392   2016 6 
49    2016 7 
1095   2016 8 
1173   2016 9 
859   2016 10 
605   2016 11 
100   2016 12 

我需要得到level1count顯示如下：

1,1,1,1,34,1392,49,1095,1173,859,605,100

使用PHP - 我剛剛開始使用PHP和開發在其中放置一個網站。我在想，也許它需要放入一個數組，然後以某種方式迴應？

對不起，如果這是一個愚蠢的問題，但正如我所說 - PHP非常新，並慢慢掌握它。

非常感謝

JS

Answer 1

這將這樣的伎倆：

<?php 
$servername = "localhost"; 
$username = "username"; 
$password = "password"; 
$dbname = "myDB"; 

// Create connection 
$db_connection = new mysqli($servername, $username, $password, $dbname); 

// Check connection 
if ($db_connection->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 

$sql = "your query here"; 
$result = $db_connection->query($sql); 
$arrLevel1 = []; 

if ($result->num_rows > 0) { 
    while($row = $result->fetch_assoc()) { 
     array_push($arrLevel1, $row['level1count']; 

} else { 
    echo "0 results"; 
} 
$comma_separated = implode(",", $arrLevel1); 
echo $comma_separated; 
$conn->close(); 
?> 

*請記住查詢只是爲了讓事情變得簡單的例子。這是不安全的，並允許SQL注入。