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我是Spring的新手,我正在開發虛擬Bank交易項目。現在,我創建了一個歡迎頁面,將我鏈接到可以進行存款或取款交易的頁面。數據庫和一切工作正常。而且,我有一張表格,顯示具有4個屬性(id,name,acctNo,balance)的客戶列表。該ID鏈接到下一頁,我只想顯示有關此客戶的信息。我怎樣才能做到這一點。Spring MVC-如何解析視圖?
的調度-servlet.xml的是:
<?xml version="1.0" encoding="UTF-8"?>
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"
xmlns:p="http://www.springframework.org/schema/p">
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<bean id="urlMapping"
class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="interceptors">
<list>
<ref local="localeChangeInterceptor"/>
</list>
</property>
<property name="urlMap">
<map>
<entry key="/login.html">
<ref bean="userloginController"/>
</entry>
</map>
</property>
</bean>
<!-- I tried adding this bean but noe luck, not sure where to use this id to map this bean -->
<bean id="showindividualCustomer" class="com.showCustomerController">s
<property name="successView"> <value>ViewCustomer</value></property>
</bean>
<bean id="userloginController" class="com.UserLoginFormController">
<property name="sessionForm"><value>false</value></property>
<property name="commandName"><value>userLogin</value></property>
<property name="commandClass"><value>com.UserLogin</value></property>
<property name="formView"><value>userLogin</value></property>
<property name="successView"><value>showCustomer</value></property>
</bean>
<bean id="localeChangeInterceptor" class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="hl"/>
</bean>
<bean id="localeResolver" class="org.springframework.web.servlet.i18n.SessionLocaleResolver"/>
</beans>
而對於豆控制器= showindividualcustomer是:
public class showCustomerController extends SimpleFormController{
protected ModelAndView onSubmit(Object obj) throws ServletException{
return new ModelAndView("ViewCustomer");//name of the jsp page inside WEB-INF/jsp
}
}
謝謝!
謝謝您的建議,但您能否爲我提供Spring 2.x中的解決方案 – 2013-02-10 22:58:49
已針對spring 2.0進行了更新 – 2013-02-11 05:12:19