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我有一個模塊，我輸出並有一個方法editHeroImage，我試圖使用mocha,chai和sinon測試。模塊有兩個作爲參數傳遞的對象，connection和queries。這些是mySql對象，其中一個包含與數據庫的連接，另一個包含在其單獨模塊中定義的查詢字符串。我正在導出並試圖測試的expObj是一個「幫手」模塊。nodejs - 測試失敗但回調被調用
我已經成功測試了此模塊的其他方法，與我試圖測試此方法的方式相同，但是，當我遇到由於某種原因而使用async模塊的方法時，我的測試不再按預期運行。我想知道在這種情況下我是否缺少了一些東西，因爲我測試了其他模塊和方法，它們也使用了async，但沒有遇到這種情況。
當我運行測試時，它記錄「你好！」如預期的那樣，但是稱爲callbackSpy的斷言失敗。
我在這裏失去了我的想法！請幫忙！到底是怎麼回事？試衣之間是否會有污染？被測
方法：
expObj.editHeroImage = function(connection, queries, postId, postData, callback) {
async.waterfall([
function(next) {
var qString = queries.getSinglePostById();
connection.query(qString, [postId], function(err, results) {
if (err) {
return next(err);
}
if (!results.length) {
console.log('NO POST FOUND WITH ID ' + postId);
return callback();
}
next(null, results[0].hero_image);
});
},
function(heroImageId, next) {
if (!heroImageId) {
console.log('HERO IMAGE IS NEW - NEXT TICK!');
return next();
}
// Delete resized images of hero image
var queryStr = queries.deleteResizedImages();
var resizedVals = [heroImageId];
connection.query(queryStr, resizedVals, function(err) {
if (err) {
return callback(err);
}
console.log('DELETED RESIZED IMAGES OF HERO IMAGE ' + heroImageId);
var qString = queries.updateHeroImagePath();
var values = [postData.hero_image, heroImageId];
return connection.query(qString, values, function(err, results) {
if (err) {
return next(err);
}
console.log('UPDATED HERO IMAGE ' + heroImageId + ' WITH PATH ' + postData.hero_image);
next('break');
});
});
},
function addHeroImage(next) {
var qString = queries.insertImage();
var values = [postData.hero_image, postId];
connection.query(qString, values, function(err, results) {
if (err) {
return next(err);
}
next(null, results.insertId);
});
},
function addHeroImagePathToPost(heroImageId, next) {
var qString = queries.saveHeroImageId();
var values = [heroImageId, postId];
connection.query(qString, values, function(err) {
if (err) {
return next(err);
}
next();
});
}
], function(err) {
if (err && err !== 'break') {
return callback(err);
}
console.log('HELLO!');
callback(null);
});
};
測試，與設置：
'use strict';
var chai = require('chai');
var sinonChai = require("sinon-chai");
var proxyquire = require('proxyquire');
var sinon = require('sinon');
chai.use(sinonChai);
var expect = chai.expect;
describe('HELPERS', function() {
var testedModule,
callbackSpy,
fakeConnectionObj,
fakeQueriesObj,
fakePost,
fakeSnakeCaseObj,
queryStub,
connectionStub,
manageStub,
fakeCamelCaseObj;
beforeEach(function() {
fakePost = {};
fakeConnectionObj = {};
fakeQueriesObj = {
getPostIdFromImage: function() {},
insertResizedImages: function() {},
createPost: function() {},
getPostImages: function() {},
getPostsAlternativesImages: function() {},
getSinglePostById: function() {},
getAllImages: function() {},
insertImage: function() {},
deleteMainImage: function() {},
deleteResizedImages: function() {},
updateHeroImagePath: function() {},
saveHeroImageId: function() {}
};
afterEach(function() {
queryStub.resetBehavior();
});
fakeSnakeCaseObj = {
sub_title: '123',
hero_image: '456'
};
fakeCamelCaseObj = {
subTitle: '123',
heroImage: '456'
};
callbackSpy = sinon.spy();
queryStub = sinon.stub();
manageStub = sinon.stub();
connectionStub = {query: queryStub};
testedModule = proxyquire('./../../../../lib/modules/mySql/workers/helpers', {
'./../../../factories/notification-service': {
select: function() {
return {manageSns: manageStub};
}
}
});
});
it('edits hero image', function() {
var _post = {
id: '123',
title: 'vf',
sub_title: 'vf',
slug: 'vf',
reading_time: 4,
created_at: '123',
published_at: '123',
deleted_on: false,
hero_image: 'hero_image_path'
};
var _postId = '123';
queryStub.onCall(0).callsArgWith(2, null, [{hero_image: '55'}]);
queryStub.onCall(1).callsArgWith(2, null);
queryStub.onCall(2).callsArgWith(2, null);
testedModule.editHeroImage(connectionStub, fakeQueriesObj, _postId, _post, function() {
console.log(arguments); // --> {'0': null} as expected
callbackSpy.apply(null, arguments);
});
expect(callbackSpy).has.been.calledWith(null);
});
});
事實上，你是正確的是它是一個時間問題。然而，使用您在斷言中包裝斷言的建議並使用before函數來設置測試會導致我的存根不再正常工作。然而，考慮到你對時間考慮的建議，我設法通過在我的測試套裝中使用'done'回調來解決問題。 – hyprstack