SAS日期約定和計算

Question

我想做一些日期計算。但以下數據類型不適用於日期計算。

data character; 
    length id time1 time2 $ 30; 
    input id $ 1 time1 $ 4-23 time2 $ 28-46; 
cards; 
7 2013-11-07 11:49:28 2014-11-01 10:29:20 
6 2014-09-14 07:36:21 2014-11-01 10:29:20 
1 2014-10-14 09:36:21 2014-11-01 10:29:20 
4 2011-04-14 04:36:21 2014-11-01 10:29:20 
8 2012-02-14 17:36:21 2014-11-01 10:29:20 
; 
run; 

我想要做的是計算此間隔之間有多少分鐘或幾小時。

data character2; 
set character; 
informat dateVar1 dateVar2 date9.; 
format dateVar1 dateVar2 date9.; 
dateVar1 = input(substr(time1,1,10), ymddttm24.); 
dateVar2 = input(substr(time2,1,10), ymddttm24.); 
/* interval=intck('day',dateVar1,dateVar2);*/ 
run; 

Answer 1

你可以這樣做：

data character; 
    input @1 id $1. @4 date1 yymmdd10. @15 time1 hhmmss10. @27 date2 yymmdd10. @38 time2 hhmmss10.; 
    datetime1 = date1 *24*3600 + time1; 
    datetime2 = date2 *24*3600 + time2; 
    format datetime1 datetime2 datetime.; 
    drop date1 time1 date2 time2; 
cards; 
7 2013-11-07 11:49:28 2014-11-01 10:29:20 
6 2014-09-14 07:36:21 2014-11-01 10:29:20 
1 2014-10-14 09:36:21 2014-11-01 10:29:20 
4 2011-04-14 04:36:21 2014-11-01 10:29:20 
8 2012-02-14 17:36:21 2014-11-01 10:29:20 
; 
run; 

Answer 2

您也可以與時針，分針和秒針功能使用DHMS函數串聯。

DATA CHARACTER; 
INPUT @1 ID $1. @3 DATE1 : YYMMDD10. @14 TIME1 : HHMMSS10. @24 DATE2 : YYMMDD10. @35 TIME2 : HHMMSS10.; 
DATETIME1 = DHMS(DATE1,HOUR(TIME1),MINUTE(TIME1),SECOND(TIME1)); 
DATETIME2 = DHMS(DATE2,HOUR(TIME2),MINUTE(TIME2),SECOND(TIME2)); 
FORMAT DATE1 DATE2 DATE9. TIME1 TIME2 TIME8. DATETIME1 DATETIME2 DATETIME.; 
/*DROP DATE1 TIME1 DATE2 TIME2;*/ 
CARDS; 
7 2013-11-07 11:49:28 2014-11-01 10:29:20 
6 2014-09-14 07:36:21 2014-11-01 10:29:20 
1 2014-10-14 09:36:21 2014-11-01 10:29:20 
4 2011-04-14 04:36:21 2014-11-01 10:29:20 
8 2012-02-14 17:36:21 2014-11-01 10:29:20 
; 
RUN;