一個很好的方式來釋放燈具

Question

嘿，我的問題如下， 我想創建代碼，其中一組運動裝置創建日期。 假設我有8支球隊，有7輪比賽。

我已經生成了燈具，但想在它們上添加日期生成。 因此，如果我有7輪，我會放28天，它會從現在開始，從現在開始的8天，每4天等。

什麼是最好的方式去做這件事？從 感謝

Answer 1

這應該做你想要什麼，並允許奇數隊伍。日期可能並不完美，因爲四捨五入：

$teams = array("TEAM A","TEAM B","TEAM C","TEAM D","TEAM E", "TEAM F","TEAM G","TEAM H","TEAM I"); 
    $days = 28; 
    $rounds = count($teams) -1; 

    //Number of Days Between Fixtures 
    $daysBetweenFixtures = floor($days/$rounds); 


    $fixtures = array(); 

    for($i =0; $i < count($teams); $i++) { 
     //Calculate Date of this round of fixtures 
     $date = date("D d M Y",mktime(0, 0, 0, date("m") , date("d")+ ($i * $daysBetweenFixtures) , date("Y"))); 

     $hasFixtureToday = array(); 

     for($j=$i; $j<$i+count($teams); $j=$j+2) { 
      $homeTeam = $teams[$j % count($teams)];   
      $awayTeam = $teams[($j+1) % count($teams)]; 

      if(!in_array($homeTeam,$hasFixtureToday) && !in_array($awayTeam,$hasFixtureToday)) { 
       $fixtures[$date][] = "{$homeTeam} vs {$awayTeam}"; 
       $hasFixtureToday[] = $homeTeam; 
       $hasFixtureToday[] = $awayTeam; 
      } 
     } 
    } 
    print_r($fixtures); 

Answer 2

例使用的strtotime（）PHP-CLI：

php > echo date("Y-m-d", strtotime("+4 days")); 
2010-05-02 

php > echo date("Y-m-d", strtotime("+8 days")); 
2010-05-06 

php > echo date("Y-m-d", strtotime("+12 days")); 
2010-05-10