Swift JSONSerialization.jsonObject錯誤

Question

我環顧四周，但我找不到解決這個一直在困擾我的錯誤的答案。我嘗試添加「as！NSMutableArray」，但那給了我另一個錯誤。任何想法如何解決它？我將我的項目從Objective-C轉換爲Swift，希望代碼很好，我現在有20多個錯誤，現在只有3個錯誤。謝謝。

錯誤消息：

'jsonObject' produces 'Any', not the expected contextual result type 'NSMutableArray' 

代碼從服務器檢索數據

// Retrieving Data from Server 
func retrieveData() { 

    let getDataURL = "http://ip/example.org/json.php" 
    let url: NSURL = NSURL(string: getDataURL)! 

    do { 

     let data: NSData = try NSData(contentsOf: url as URL) 
     jsonArray = JSONSerialization.jsonObject(with: data, options: nil) 
    } 
    catch { 
     print("Error: (data: contentsOf: url)") 
    } 

    // Setting up dataArray 
    var dataArray: NSMutableArray = [] 

    // Looping through jsonArray 
    for i in 0..<jsonArray.count { 

     // Create Data Object 

     let dID: String = (jsonArray[i] as AnyObject).object(forKey: "id") as! String 
     let dName: String = (jsonArray[i] as AnyObject).object(forKey: "dataName") as! String 
     let dStatus1: String = (jsonArray[i] as AnyObject).object(forKey: "dataStatus1") as! String 
     let dStatus2: String = (jsonArray[i] as AnyObject).object(forKey: "dataStatus2") as! String 
     let dURL: String = (jsonArray[i] as AnyObject).object(forKey: "dataURL") as! String 

     // Add Data Objects to Data Array 
     dataArray.add(Data(dataName: dName, andDataStatus1: dStatus1, andDataStatus2: dStatus2, andDataURL: dURL, andDataID: dID)) 
    } 

    self.myTableView.reloadData() 
} 

Answer 1

jsonObject該函數將返回類型Any但jsonArray的值的類型NSMutableArray。如果出現問題，此功能會引發錯誤，請在其前面輸入try關鍵字。根據我的經驗，將jsonArray的類型更改爲字典數組，以便輕鬆提取數據。

do { 
     let data: Data = try Data(contentsOf: url as URL) 
     let jsonArray: [[String: AnyObject]] = try JSONSerialization.jsonObject(with: data, options: .mutableContainers) as! [[String: AnyObject]] 
     print("json: \(jsonArray)") 

     for dict in jsonArray { 
      let dataName = dict["dataName"] as! String 
      print("dataName: \(dataName)") 
     } 
    } 
    catch { 
     print("Error: (data: contentsOf: url)") 
    }