3
做這種事情的語法是什麼?當我嘗試編譯下面的代碼時,它告訴我a ';' was expected before '*'
指向函數的返回類型ResourceManager<T>::ResourceWrapper*
。C++:返回指向模板子類的指針
template<class T>
class ResourceManager
{
private:
struct ResourceWrapper;
ResourceWrapper* pushNewResource(const std::string& file);
};
// (Definition of ResourceWrapper not shown.)
template <class T>
ResourceManager<T>::ResourceWrapper* ResourceManager<T>::pushNewResource(
const std::string& file)
{
// (Irrelevant details)
}