簡化普通的地圖轉換爲嵌套地圖

Question

我需要簡單的地圖轉換與環境變量的代碼

HOST_IDX  :"192.168.99.100", 
    PORT_IDX_HTTPS:"9447", 
    HOST_ESB  :"192.168.99.100", 
    PORT_ESB_HTTPS:"8245", 
    PORT_ESB_HTTP :"8282", 
    OTHER   :"foo" 

到嵌套的地圖，在JSON看起來是這樣的：

{ 
    "idx": { 
     "host": "192.168.99.100", 
     "port": { 
      "https": "9447" 
     } 
    }, 
    "esb": { 
     "host": "192.168.99.100", 
     "port": { 
      "https": "8245", 
      "http": "8282" 
     } 
    } 
} 

它下面的代碼，實際上這樣做，但我想盡量減少/簡化它...

def env=[ 
    HOST_IDX:"192.168.99.100", 
    PORT_IDX_HTTPS:"9447", 
    HOST_ESB:"192.168.99.100", 
    PORT_ESB_HTTPS:"8245", 
    PORT_ESB_HTTP:"8282", 
    OTHER:"foo" 
] 

def x=env 
    .collectEntries{[it.key.toLowerCase().split('_'),it.value]} 
    .findAll{it.key[0] in ['host','port']} 
    .groupBy({it.key[1]}, {it.key[0]}) 
    .collectEntries{[ 
      it.key, it.value.collectEntries{[ 
       it.key, it.key=='host' ? it.value.entrySet()[0].value : it.value.collectEntries{[ 
        it.key[-1], it.value 
       ]} 
      ]} 
     ]} 

println new groovy.json.JsonBuilder(x).toPrettyString() 

Answer 1

如果您最初的鑰匙將有正確的順序（IDX_PORT_HTTPS而不是 PORT_IDX_HTTPS），你可以只設置它們具有「嵌套「放。所以你可以 拆分_像你已經和swap(0,1)頭兩個要素。然後使用 作爲路徑將值設置爲映射。例如：

def env=[ 
    HOST_IDX:"192.168.99.100", 
    PORT_IDX_HTTPS:"9447", 
    HOST_ESB:"192.168.99.100", 
    PORT_ESB_HTTPS:"8245", 
    PORT_ESB_HTTP:"8282", 
] 

// simplified nested put 
def assocIn(m, path, v) { 
    path.dropRight(1).inject(m){p,k->p.get(k,[:])}.put(path.last(), v) 
    return m 
} 

// split the keys and swap the first two elements to get a path to use 
// for a nested put 
println(env.inject([:]){ m, it -> 
    assocIn(m, it.key.toLowerCase().split("_").swap(0,1), it.value) 
}) 

Answer 2

這個問題是border-line subje莫如/堅持己見，但表示鑑於這個問題，爲什麼不這樣做：

def x = [ 
    "idx" : ["host" : env["HOST_IDX"], 
      "port" : ["https" : env["PORT_IDX_HTTPS"]]], 
    "esb" : ["host" : env["HOST_IDX"], 
      "port" : ["https" : env["PORT_ESB_HTTPS"], 
         "http" : env["PORT_ESB_HTTP"]]] 
] 

println new groovy.json.JsonBuilder(x).toPrettyString()