python capture URLError code

我想用Python來監視使用HTTPS的網站。問題是，網站上的證書無效。我不在乎，我只是想知道網站正在運行。python capture URLError code

我工作的代碼如下所示：

from urllib.request import Request, urlopen 
from urllib.error import URLError, HTTPError 
req = Request("https://somedomain.com") 

try: 
    response = urlopen(req) 
except HTTPError as e: 
    print('server couldn\'t fulfill the request') 
    print('error code: ', e.code) 
except URLError as e: 
     print(e.args)  
else: 
    print ('website ok')

，在URLError結束被調用。錯誤代碼是645.

C:\python>python monitor443.py 
(SSLError(1, '[SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:645)'),)

所以，我試圖除了代碼645以外。我已經試過這樣：

from urllib.request import Request, urlopen 
from urllib.error import URLError, HTTPError 
req = Request("https://somedomain.com") 

try: 
    response = urlopen(req) 
except HTTPError as e: 
    print('server couldn\'t fulfill the request') 
    print('error code: ', e.code) 
except URLError as e: 
     if e.code == 645: 
      print("ok") 
     print(e.args)  
else: 
    print ('website ok')

，但得到這個錯誤：

Traceback (most recent call last): 
    File "monitor443.py", line 11, in <module> 
    if e.code == 645: 
AttributeError: 'URLError' object has no attribute 'code'

如何添加此異常？

來源

2016-08-04 Shawn

['URLError'是OSERROR的一個子類（http://stackoverflow.com/q/38773209/344286）可能會說，它是在['e.errno'發現]（https://docs.python.org/3/library/exceptions.html#OSError.errno）？ –

e.errno返回「none」 – Shawn

另外... 645不是errorno，那是錯誤發生的C源代碼行，AFAIK。 –

請看看偉大的requests包。這會在進行http通信時簡化您的生活。見http://requests.readthedocs.io/en/master/。

pip install requests

要跳過證書檢查，你會做這樣的事情（注意verify參數！）：

requests.get('https://kennethreitz.com', verify=False) 
<Response [200]>

查看完整的文檔here。

HTH

來源

2016-08-04 17:27:46 ferdy

我無法安裝SLL庫（egg_info錯誤）。這是我最後做

from urllib.request import Request, urlopen 
from urllib.error import URLError, HTTPError 

def sendEmail(r):  
    #send notification 
    print('send notify') 

req = Request("https://somedomain.com") 

try: 
    response = urlopen(req) 
except HTTPError as e: 
    print('server couldn\'t fulfill the request') 
    print('error code: ', e.code) 
    sendEmail('server couldn\'t fulfill the request') 
except URLError as e: 
     theReason=str(e.reason) 
     #[SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:645) 
     if theReason.find('CERTIFICATE_VERIFY_FAILED') == -1: 
      sendEmail(theReason) 
     else: 
      print('website ok')   
else: 
    print('website ok')

來源

2016-08-04 18:28:13 Shawn

python capture URLError code

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