x<-sample(30:60,50,TRUE)
y<-cut(x,breaks=c(30,40,50,60))
y
[1] (30,40] (30,40] (50,60] (40,50] (40,50] (40,50] (40,50] (30,40] (30,40]
[10] (50,60] (30,40] (50,60] (30,40] (30,40] (50,60] (50,60] (50,60] (30,40]
[19] (50,60] (30,40] (40,50] (40,50] (30,40] (30,40] (30,40] (40,50] (30,40]
[28] (50,60] (40,50] (40,50] (30,40] (50,60] (40,50] (50,60] (50,60] (30,40]
[37] (50,60] (50,60] (30,40] (50,60] (30,40] (30,40] <NA> (40,50] (30,40]
[46] (40,50] (30,40] (30,40] (30,40] (30,40]
Levels: (30,40] (40,50] (50,60]
table(y)
y
(30,40] (40,50] (50,60]
23 12 14
table(y)[1]
(30,40]
23
問題1:剪切和表功能
如果右= FALSE被添加,所述間隔是
(30,40](40,50](50,60]
如果右= TRUE被添加,所述間隔是
[30,40)[40,50)[50,60)
我怎樣才能獲得的間隔如[30,40] (40,50] (50,60]
或「[30,40)[40,50 )[50,60]`?
問題2:?
table(y)[1]
(30,40]
23
我知道有23個號碼在區間(30,40],我可以讓他們所有 x[x<=40 & x>30]
有沒有更好的方式來獲得結果
將'include.lowest'參數設置爲'TRUE'? – Arun 2013-04-06 07:47:49
問題1解決了,問題2呢? – 2013-04-06 07:51:23
該參數只包含'[30,40]'(最低)。它仍然是'(40,50')和'(50,60'),我不確定這是否是你想要的,你能告訴你到底想要什麼嗎?你想能夠從30到40,和40 - 50等。 – Arun 2013-04-06 08:00:51