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我創建了一個彈出的gtkdialogbox,提示用戶輸入。 這裏是我的代碼:gtk_entry_set_activates_default沒有做到神奇
GtkWidget *button = gtk_button_new_with_label ("add a new button");
//adding a new button
GtkWidget * new_button_dialog = gtk_dialog_new_with_buttons("new button",(GtkWindow *)container,GTK_DIALOG_DESTROY_WITH_PARENT,"OK", GTK_RESPONSE_NONE,NULL);
GtkWidget * content_area = gtk_dialog_get_content_area (GTK_DIALOG (new_button_dialog));
GtkWidget * button_name_label = gtk_label_new ("Press escape at any time to cancel.\ntype in the button name");
gtk_container_add (GTK_CONTAINER (content_area) , button_name_label);
GtkWidget * button_name_entry = gtk_entry_new();
gtk_entry_set_activates_default((GtkEntry*)button_name_entry,TRUE);
gtk_container_add(GTK_CONTAINER(content_area), button_name_entry);
問題是我tryign當用戶按下輸入 gtk_entry_set_activates_default 當我按下回車(當上述項目已經集中)接受輸入我什麼也沒得到
感謝
您指定的「OK」按鈕,對話框的默認窗口小部件? – ptomato
我認爲我沒有這樣做,我該怎麼做? –
'gtk_widget_grab_default(ok_button);' – ptomato