我會在這裏給你一個AJAX的整體流程。我試圖提供意見,以顯示控制流程。
<select id="selectOption"> //******* Assign an ID
<?php $taskStatus = "SELECT * FROM task_status WHERE used = 1 ORDER BY id ASC ";
$taskresults = $conn->query($taskStatus) or die(mysqli_error($conn));
while($taskStatusRow = mysqli_fetch_assoc($taskresults)) {
echo " <option value= ". $taskStatusRow['name'] ." >". $taskStatusRow['name'] ." </option>";
}
?>
</select>
的jQuery + AJAX
$(document).ready(function() {
$("#selectOption").change(function(){ //** on selecting an option based on ID you assigned
var optionVal = $("#selectOption option:selected").val(); //** get the selected option's value
$.ajax({
type: "POST", //**how data is send
url: "MYPROCESSPAGE.php", //** where to send the option data so that it can be saved in DB
data: {optionVal: optionVal }, //** send the selected option's value to above page
dataType: "json",
success: function(data){
//** what should do after value is saved to DB and returned from above URL page.
}
});
});
});
裏面你MYPROCESSPAGE.php
,您可以訪問通過AJAX方式通數據:
<?php
$selectedOptionVal = $_POST['optionVal'];
//DB CONNECTION STEPS
.
.
.
// You are trying to "UPDATE" a table data based on some ID and not inserting. Included both operations
// If you are INSERTING A new table entry, use below code.
//INSERT INTO snagging (taskstatus, updated_at) VALUES ('$selectedOptionVal', 'Now()');
// If you are UPDATING an existing table entry, use below code.
//UPDATE snagging SET taskstatus = '$selectedOptionVal', updated_at = 'Now()' WHERE ID = 1234;
?>
希望這是有幫助的。
那麼,AJAX涉及JavaScript所以...你的JavaScript代碼在哪裏? – Mikey
我不知道如何處理JS..so –
然後它看起來像它回到書籍和教程。它真的不是火箭科學 – RiggsFolly