變化speechSynthesis語音與語音識別

我使用語音識別與我的麥克風，並具有中繼回我speechSynthesis數據。變化speechSynthesis語音與語音識別

我所做的聲音是一個女聲在頁面加載，並希望能夠通過說「男聲」，然後將接力「我現在是一個人」，切換到一個男性的聲音。我後來也希望能夠做相反的事情 - 當它設定爲男性的聲音時，說出「女性的聲音」，然後切換回來。

我目前能做到這一點，但男聲將只說了一次的聲音不被保存，僅作爲參數傳遞。因此，然後說出接下來的事情會回來的女聲：

let voices = []; 
window.speechSynthesis.onvoiceschanged = function() { 
    voices = window.speechSynthesis.getVoices(); 
}; 

function loadVoices(message, voice) { 
    const msg = new SpeechSynthesisUtterance(); 
    msg.voice = voice || voices[48]; // female voice 
    msg.text = message; 
    speechSynthesis.speak(msg); 
}; 

// asking for voice change here 
    if (transcript.includes('male voice')) { 
    let message = ('I am now a man'); 
    let voice = voices[50]; // male voice 
    loadVoices(message, voice); 
    }

我想有一個全局變量，使得msg.voice指向一個全局變量，但是，這並不工作，再加上聲音將恢復爲默認值（電子語音）：

let voiceGender = voices[48]; 
function loadVoices(message) { 
    const msg = new SpeechSynthesisUtterance(); 
    msg.voice = voiceGender // now a variable pointing to another. 
    msg.text = message; 
    speechSynthesis.speak(msg); 
}; 

    if (transcript.includes('male voice')) { 
    let message = ('I am now a man'); 
    let voiceGender = voices[50]; // changing the global variable 
    loadVoices(message); 
    }

如果我聲明voiceGender的loadVoices()內，然後我不能從if這是另一個函數內變化。

如何設置的JavaScript結構，這樣我可以做到這一點？

// on pageload the voice is set to a female voice 
let femaleVoice = true; 

function loadVoices(message) { 
    const msg = new SpeechSynthesisUtterance(); 

    // checks the boolean 
    if (femaleVoice) { 
    msg.voice = voices[48]; 
    } else { 
    msg.voice = voices[50]; 
    } 

    msg.text = message; 
    speechSynthesis.speak(msg); 
}; 

// changes the boolean/changes the gender of the SpeechSynthesisUtterance voice 
function changeVoice() { 
    if (femaleVoice) { 
    femaleVoice = false; 
    } else { 
    femaleVoice = true; 
    } 
} 

if (transcript.includes('male voice') || transcript.includes('female voice')) { 
    // calls the function to change the boolean. 
    changeVoice(); 

    let message = ('I now have a different voice'); 
    loadVoices(message); 
}

它確實增加了更多一點點線比原來想，但肯定的作品：

來源

2017-08-31 Maxime Dore

我加入一個函數和一個布爾值與在loadVoices功能，使得條件來解決它。

來源

2017-09-06 14:16:22

變化speechSynthesis語音與語音識別

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