從多個列組合中選擇表中的數據

Question

我試圖從基於height和width列的多個組合的表中選擇數據。但是，我正在使用的查詢不起作用。

$sql_wallpaper = " 
    SELECT * 
    FROM wallpaper 
    WHERE categoryid = $catid 
    WHERE height = 1080 
    OR width = 2560 
    OR width = 1366 
    OR height = 720 
    OR width = 2560 
    AND height = 1600 
    OR width = 1680 
    AND height = 1050 
    OR width = 1920 
    AND height = 1200 
    OR width = 1280 
    AND height = 800 
    OR width = 1440 
    AND height = 900 
    ORDER BY wallpaperid DESC 
    LIMIT $from,$max_results 
"; 

我該如何解決這個問題？

Answer 1

這是因爲你的SQL是錯誤的：

select * from wallpaper 
    where categoryid = $catid 
    where height = 1080 OR width = 2560 OR width = 1366 
    OR height = 720 OR width = 2560 AND height = 1600 
    OR width = 1680 AND height = 1050 OR width = 1920 
    AND height = 1200 OR width = 1280 AND height = 800 
    OR width = 1440 AND height = 900 
    order by wallpaperid desc 
    limit $from,$max_results 

你在那裏有兩個WHERE秒。您應該使用AND代替第二個，也許將所有內容都包裝成parens。

但也可以嘗試在腳本中使用print mysql_error()。尤其對於某些不起作用的調試。 MySQL會在大多數時候告訴你你的查詢有什麼問題。

---

很好。您的重寫查詢：

select * from wallpaper 
    where categoryid = $catid 
    AND (
     height = 1080 OR width = 2560 OR width = 1366 
    OR height = 720 OR width = 2560 AND height = 1600 
    OR width = 1680 AND height = 1050 OR width = 1920 
    AND height = 1200 OR width = 1280 AND height = 800 
    OR width = 1440 AND height = 900 
     ) 
    order by wallpaperid desc 
    limit $from,$max_results 

但你可能需要使用簡單的是：

SELECT * FROM wallpaper 
    WHERE categoryid = $catid 
    AND width IN (1440, 2560, 1366, 1680, 1920, 1280) 
    AND height IN (1200, 800, 900, 1080, 720, 1600, 1050) 
    ORDER BY wallpaperid DESC 
    LIMIT $from,$max_results