2016-11-14 91 views
0

希望有人幫助我,我無法繞過這個。帶附加選項的實體字段

我正在使用Symfony 3.1.6。

我有兩個實體,地區和城市,關係一對多。我有一個表單,加載區域的選擇框,並在選擇至極區域的功能顯示該地區的城市。這很好。

我已通過finishView()向城市組合框中添加了一個選項,以便爲用戶提供oportunity,如果他的城市未列出,則選擇此選項並輸入出現的輸入提供添加的可能性一個新的城市。此選項值爲0.

但是,當表單被引用時,會顯示一個錯誤,並顯示「此值無效」。我認爲這是因爲沒有任何區域的id = 0的任何城市的選項的價值。然後,我需要的是禁用/消除/這是什麼驗證,但我不知道該怎麼做。

我已經tryed:

$builder->addEventListener(FormEvents::POST_SUBMIT, function (FormEvent $event) { 
     $event->stopPropagation(); 
    }, 900); 

但沒有工作....

顯然,我可以去ChoiceType代替的EntityType,消除實體或其他不那麼優雅的方式之間的關係解決此問題。但我確信有一種方法,這是Symfony。

編輯1:添加的locationType

<?php 
namespace AppBundle\Form; 

use Symfony\Component\Form\AbstractType; 
use Symfony\Component\Form\FormBuilderInterface; 
use Symfony\Component\Form\FormEvent; 
use Symfony\Component\Form\FormEvents; 
use Doctrine\ORM\EntityRepository; 
use Symfony\Component\Form\Extension\Core\Type\CountryType; 
use Symfony\Component\Form\Extension\Core\Type\TextType; 
use Symfony\Bridge\Doctrine\Form\Type\EntityType; 
use Symfony\Component\Form\FormView; 
use Symfony\Component\Form\FormInterface; 
use Symfony\Component\Form\ChoiceList\View\ChoiceView; 

class LocationType extends AbstractType 
{ 

public function buildForm(FormBuilderInterface $builder, array $options) 
{ 

    $region_options = array(
     'class' => 'AppBundle:Region', 
     'choice_label' => 'name', 
     'label' => 'Region', 
     'translation_domain' => 'messages', 
     'required' => true, 
     'mapped' => false, 
    ); 

    $city_options = array(
     'class' => 'AppBundle:City', 
     'choice_label' => 'name', 
     'label' => 'City', 
     'translation_domain' => 'messages', 
     'required' => true, 
     'mapped' => false, 
    ); 

    $alt_city_options = array(
     'required' => false, 
     'mapped' => true, 
     'label' => 'Alternative city', 
     'translation_domain' => 'messages', 
     'attr' => array(
      'placeholder' => 'Enter your city name', 
     ), 
    ); 

    $builder->addEventListener(
     FormEvents::PRE_SET_DATA, 
     function (FormEvent $event) use ($region_options, $city_options, $alt_city_options) { 
      $form = $event->getForm(); 
      $data = $event->getForm()->getParent()->getData(); 

      $country = '332'; 

      $region_options['query_builder'] = function (EntityRepository $er) use ($country) { 
        return $er->createQueryBuilder('r') 
         ->where('r.country = :country') 
         ->setParameter('country', $country) 
         ->orderBy('r.name', 'ASC'); 
       }; 

       if (!empty($data->getRegion())) { 
        $region_options['data'] = $data->getRegion()->getId(); 
       } 
       $form->add('region', EntityType::class, $region_options); 
      } 

      if (!empty($data->getRegion())) { 
       $region = $data->getRegion(); 
       $city_options['query_builder'] = function (EntityRepository $er) use ($country, $region) { 
        return $er->createQueryBuilder('c') 
         ->where('c.country = :country') 
         ->andWhere('c.region = :region') 
         ->setParameter('country', $country) 
         ->setParameter('region', $region) 
         ->orderBy('c.name', 'ASC'); 
       }; 

       if (!empty($data->getCity())) { 
        $region_options['data'] = $data->getCity()->getId(); 
       } 
       $form->add('city', EntityType::class, $city_options); 
      } 
      $form->add('alt_city', TextType::class, $alt_city_options); 
     } 
    ); 

    $builder->addEventListener(FormEvents::POST_SUBMIT, function (FormEvent $event) { 
     $event->stopPropagation(); 
    }, 900); 
} 

public function finishView(FormView $view, FormInterface $form, array $options) 
{ 
    $new_choice = new ChoiceView(array(), '0', 'not_in_the_list'); 
    $view->children['city']->vars['choices'][] = $new_choice; 
} 

}

希望這有助於。

回答

0

您可以將我們的EntityType字段定義粘貼到我們嗎?

這可能有助於解決問題。

要設置的EntityType場,你必須指定下列選項:

  • CHOICE_LABEL(除非你有一個__toString在實體()函數)